docker-compose命令中的变量替换

Question

我需要将文件中的env变量传递给docker-compose中的命令，但这似乎是不可能的。因此，我先尝试使用var环境，但此方法无法再次使用。我该怎么办？

version: '3'
services:
  nginx-service-xxx:
    image: service-xxx-nginx:latest
    ports:
      - 80:80
    restart: always

  service-xxx:
    image: service-xxx:latest
#    env_file:
#        - db-settings.env
    environment:
      - PORT=80
      - PG-HOST=192.168.0.101
      - PG-DATABASE=xxx
      - PG-USER=postgres
      - PG-PASSWORD=postgres
    restart: always
    command: python xxx/main.py --port=$$PORT --pg-host=$$PG-HOST --pg-database=$$PG-DATABASE --pg-user=$$PG-USER --pg-password=$$PG-PASSWORD

Answer 1

尝试将命令的复杂性移至Docker入口点。首先，您需要在项目中添加以下入口点（使其可执行）

#!/bin/bash -e

case $1 in

  web)
    python xxx/main.py --port=$PORT --pg-host=$PG-HOST --pg-database=$PG-DATABASE --pg-user=$PG-USER --pg-password=$PG-PASSWORD
  ;;

  *)
    exec "$@"
  ;;

esac

exit 0

为您的服务更新docker文件

From base-image

COPY ./docker-entrypoint.sh /
ENTRYPOINT ["/docker-entrypoint.sh"]

更新撰写

version: '3'
services:
  nginx-service-xxx:
    image: service-xxx-nginx:latest
    ports:
      - 80:80
    restart: always

  service-xxx:
    image: service-xxx:latest
    environment:
      - PORT=80
      - PG-HOST=192.168.0.101
      - PG-DATABASE=xxx
      - PG-USER=postgres
      - PG-PASSWORD=postgres
    restart: always
    command: web