SQL Server:如何加入第一行

问题描述 投票:667回答:11

我将使用一个具体的,但假设的例子。

每个订单通常只有一个订单项:

命令:

OrderGUID   OrderNumber
=========   ============
{FFB2...}   STL-7442-1      
{3EC6...}   MPT-9931-8A

了LineItem:

LineItemGUID   Order ID Quantity   Description
============   ======== ========   =================================
{098FBE3...}   1        7          prefabulated amulite
{1609B09...}   2        32         spurving bearing

但偶尔会有一个包含两个订单项的订单:

LineItemID   Order ID    Quantity   Description
==========   ========    ========   =================================
{A58A1...}   6,784,329   5          pentametric fan
{0E9BC...}   6,784,329   5          differential girdlespring 

通常在向用户显示订单时:

SELECT Orders.OrderNumber, LineItems.Quantity, LineItems.Description
FROM Orders
    INNER JOIN LineItems 
    ON Orders.OrderID = LineItems.OrderID

我想在订单上显示单个项目。但是,由于此偶尔包含两个(或更多)商品的订单,订单将显示为重复:

OrderNumber   Quantity   Description
===========   ========   ====================
STL-7442-1    7          prefabulated amulite
MPT-9931-8A   32         spurving bearing
KSG-0619-81   5          panametric fan
KSG-0619-81   5          differential girdlespring

我真正想要的是让SQL Server选择一个,因为它足够好:

OrderNumber   Quantity   Description
===========   ========   ====================
STL-7442-1    7          prefabulated amulite
MPT-9931-8A   32         differential girdlespring
KSG-0619-81   5          panametric fan

如果我喜欢冒险,我可能会向用户显示一个省略号,表示不止一个:

OrderNumber   Quantity   Description
===========   ========   ====================
STL-7442-1    7          prefabulated amulite
MPT-9931-8A   32         differential girdlespring
KSG-0619-81   5          panametric fan, ...

所以问题是如何

  • 消除“重复”行
  • 只加入其中一行,以避免重复

第一次尝试

我的第一个天真的尝试是只加入“TOP 1”订单项:

SELECT Orders.OrderNumber, LineItems.Quantity, LineItems.Description
FROM Orders
    INNER JOIN (
       SELECT TOP 1 LineItems.Quantity, LineItems.Description
       FROM LineItems
       WHERE LineItems.OrderID = Orders.OrderID) LineItems2
    ON 1=1

但是这给出了错误:

列或前缀'Orders'没有 与表名或别名匹配 在查询中使用。

大概是因为内部选择没有看到外表。

sql sql-server tsql sql-server-2000
11个回答
1108
投票
SELECT   Orders.OrderNumber, LineItems.Quantity, LineItems.Description
FROM     Orders
JOIN     LineItems
ON       LineItems.LineItemGUID =
         (
         SELECT  TOP 1 LineItemGUID 
         FROM    LineItems
         WHERE   OrderID = Orders.OrderID
         )

SQL Server 2005及以上,您可以用INNER JOIN替换CROSS APPLY

SELECT  Orders.OrderNumber, LineItems2.Quantity, LineItems2.Description
FROM    Orders
CROSS APPLY
        (
        SELECT  TOP 1 LineItems.Quantity, LineItems.Description
        FROM    LineItems
        WHERE   LineItems.OrderID = Orders.OrderID
        ) LineItems2

请注意,没有TOP 1ORDER BY不具有确定性:此查询您将获得每个订单一个订单项,但未定义它将是哪一个。

对查询进行多次调用可以为同一订单提供不同的行项目,即使底层证券没有更改也是如此。

如果您想要确定性顺序,则应该在最里面的查询中添加ORDER BY子句。


2
投票

尝试过十字架,效果很好,但需要稍微长一些。调整后的行列具有最大值和添加组,可以保持速度并减少额外记录。

这是调整后的查询:

SELECT Orders.OrderNumber, max(LineItems.Quantity), max(LineItems.Description)
FROM Orders
    INNER JOIN LineItems 
    ON Orders.OrderID = LineItems.OrderID
Group by Orders.OrderNumber

2
投票

我通过使用LEFT JOIN和GROUP BY Orders.OrderNumber解决了类似的问题。有没有理由不这样做?

SELECT Orders.OrderNumber, LineItems.Quantity, LineItems.Description
FROM Orders
    LEFT JOIN LineItems 
    ON Orders.OrderID = LineItems.OrderID
GROUP BY Orders.OrderNumber

我会在你自己的问题中回答你的回答问题:

Orders             LineItems
+-------------+    +---------+----------+---------------+
| OrderNumber |    | OrderID | Quantity | Description   |
+-------------+    +---------+----------+---------------+
| 22586       |    | 22586   | 17       | Trunion       |
+-------------+    | 22586   | 3        | Girdle Spring |
                   +---------+----------+---------------+

在OrderNumber上将两者连接在一起给出:

OrderNumber  Quantity  Description
-----------  --------  -------------
22586        17        Trunion
22586        3         Girdle Spring

2 row(s) affected

我们希望它只返回一行:

OrderNumber  Quantity  Description
-----------  --------  -------------
22586        17        Trunion

1 row(s) affected

这就是我使用GROUP BY Orders.OrderNumber的原因,每个OrderNumber只返回一行。


103
投票

我知道这个问题已经回答了一段时间,但是在处理大型数据集时,嵌套查询的代价很高。这是一个不同的解决方案,嵌套查询只运行一次,而不是返回每一行。

SELECT 
  Orders.OrderNumber,
  LineItems.Quantity, 
  LineItems.Description
FROM 
  Orders
  INNER JOIN (
    SELECT
      Orders.OrderNumber,
      Max(LineItem.LineItemID) AS LineItemID
    FROM
      Orders INNER JOIN LineItems
      ON Orders.OrderNumber = LineItems.OrderNumber
    GROUP BY Orders.OrderNumber
  ) AS Items ON Orders.OrderNumber = Items.OrderNumber
  INNER JOIN LineItems 
  ON Items.LineItemID = LineItems.LineItemID

26
投票

你可以这样做:

SELECT 
  Orders.OrderNumber, 
  LineItems.Quantity, 
  LineItems.Description
FROM 
  Orders INNER JOIN LineItems 
  ON Orders.OrderID = LineItems.OrderID
WHERE
  LineItems.LineItemID = (
    SELECT MIN(LineItemID) 
    FROM   LineItems
    WHERE  OrderID = Orders.OrderID
  )

这需要LineItems.LineItemID上的索引(或主键)和LineItems.OrderID上的索引,否则它将很慢。


18
投票

@Quassnoi答案很好,在某些情况下(特别是如果外表很大),使用窗口函数可能会有更高效的查询,如下所示:

SELECT  Orders.OrderNumber, LineItems2.Quantity, LineItems2.Description
FROM    Orders
LEFT JOIN 
        (
        SELECT  LineItems.Quantity, LineItems.Description, OrderId, ROW_NUMBER()
                OVER (PARTITION BY OrderId ORDER BY (SELECT NULL)) AS RowNum
        FROM    LineItems

        ) LineItems2 ON LineItems2.OrderId = Orders.OrderID And RowNum = 1

有时你只是need to test哪个查询提供更好的性能。


11
投票

,另一种使用公用表表达式的方法:

with firstOnly as (
    select Orders.OrderNumber, LineItems.Quantity, LineItems.Description, ROW_NUMBER() over (partiton by Orders.OrderID order by Orders.OrderID) lp
    FROM Orders
        join LineItems on Orders.OrderID = LineItems.OrderID
) select *
  from firstOnly
  where lp = 1

或者,最后可能你想显示所有加入的行?

逗号分隔版本:

  select *
  from Orders o
    cross apply (
        select CAST((select l.Description + ','
        from LineItems l
        where l.OrderID = s.OrderID
        for xml path('')) as nvarchar(max)) l
    ) lines

8
投票

相关子查询是依赖于外部查询的子查询。它就像SQL中的for循环。对于外部查询中的每一行,子查询将运行一次:

select * from users join widgets on widgets.id = (
    select id from widgets
    where widgets.user_id = users.id
    order by created_at desc
    limit 1
)

6
投票

从SQL Server 2012开始,我认为这将解决这个问题:

SELECT DISTINCT
    o.OrderNumber ,
    FIRST_VALUE(li.Quantity) OVER ( PARTITION BY o.OrderNumber ORDER BY li.Description ) AS Quantity ,
    FIRST_VALUE(li.Description) OVER ( PARTITION BY o.OrderNumber ORDER BY li.Description ) AS Description
FROM    Orders AS o
    INNER JOIN LineItems AS li ON o.OrderID = li.OrderID

5
投票

编辑:没关系,Quassnoi有一个更好的答案。

对于SQL2K,这样的事情:

SELECT 
  Orders.OrderNumber
, LineItems.Quantity
, LineItems.Description
FROM (  
  SELECT 
    Orders.OrderID
  , Orders.OrderNumber
  , FirstLineItemID = (
      SELECT TOP 1 LineItemID
      FROM LineItems
      WHERE LineItems.OrderID = Orders.OrderID
      ORDER BY LineItemID -- or whatever else
      )
  FROM Orders
  ) Orders
JOIN LineItems 
  ON LineItems.OrderID = Orders.OrderID 
 AND LineItems.LineItemID = Orders.FirstLineItemID

3
投票

我最喜欢的运行此查询的方法是使用not exists子句。我相信这是运行此类查询的最有效方法:

select o.OrderNumber,
       li.Quantity,
       li.Description
from Orders as o
inner join LineItems as li
on li.OrderID = o.OrderID
where not exists (
    select 1
    from LineItems as li_later
    where li_later.OrderID = o.OrderID
    and li_later.LineItemGUID > li.LineItemGUID
    )

但我没有针对此处建议的其他方法测试此方法。

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