线末端的表观空间

Question

嘿，所以我通过我学校使用的代码作业网站提交我的代码，由于某种原因，它说我的行间距与金额有关，这可以在下面的截图中看到，输出在左边是预期的，右边的是我得到的。我的代码有什么问题呢？同样在我的每个输出结束时，它也会打印“无”。为什么？

Answer 1

一个问题是你的thank_donor函数返回print函数，然后你再次调用print函数。您希望该函数只返回您可以打印的纯字符串。

Answer 2

def thank_donor(first_name, last_name, amount, donor_status):
    """prints thank you note with variables in"""


    last = last_name.upper() 
    first = first_name.capitalize() 



    print(
        "----------------------------------------" +
        "\n" +

        "Note to donor:", last + ",", first +

        "\n" + 

        "----------------------------------------" +
        "\n" + 

        "Dear", first + "," + 

在这里，不要在“{：.2f}”。格式（金额）的末尾使用“，”因为它会导致空格，而是使用“+”。

        "\n" + 
        "Thank you for your donation of", "$" +  "{:.2f}".format(amount) +
        "\n" +
        "to our album campaign." +

        "\n" + 

        "This makes you a", donor_status, "member." 
        "\n" + 

        "ROCK ON," +
        "\n" +  
        "Blink 992" + 

        "\n" + 


        "========================================")

在功能和调用功能时，不要多次使用打印功能。

thank_donor("joe", "bloggs", 100, "Bronze")

Answer 3

def thank_donor(first_name, last_name, amount, donor_status):
    """prints thank you note with variables in"""

    last = last_name.upper() 
    first = first_name.capitalize()         
    return print(
        "----------------------------------------" +
        "\n" +
        "Note to donor:", last + ",", first +
        "\n" + 
        "----------------------------------------" +
        "\n" + 
        "Dear", first + "," + 
        "\n" + 
        "Thank you for your donation of", "$" +  "{:.2f}".format(amount),
        "\n" +
        "to our album campaign." +
        "\n" + 
        "This makes you a", donor_status, "member." 
         "\n" + 
        "ROCK ON," +
        "\n" +  
        "Blink 992" + 
        "\n" + 
        "========================================")

thank_donor("joe", "bloggs", 100, "Bronze")

试试这个代码。问题是你最后打印none。发生这种情况是因为你将print函数返回到另一个print函数，即print(print(#something#)。只需删除任何print语句。