我想将每两行合并成一行
表格:clock_activities
id employee_id activity created_at
1 1 start_break 1:00
2 1 end_break 1:10
3 1 start_break 2:00
4 1 end_break 2:10
5 1 start_break 2:30
6 1 end_break 2:45
7 1 start_break 3:10
8 1 end_break 3:20
我正在寻找的东西是这样的:
start end total
1:00 1:10 00:10
2:00 2:10 00:10
2:30 2:45 00:15
3:10 3:20 00:10
有人能指出我正确的方向吗?我在Stackoverflow上找不到具有相同要求的任何内容。
我将使用一个定义记录组的窗口总和来处理:每次看到'start_break'
时,都会开始一个新的组。然后可以聚合:
select
employee_id,
min(case when id = 'start_break' then created_at end) start_break,
max(case when id = 'end_break' then created_at end) end_break,
timestampdiff(
minute,
max(case when id = 'end_break' then created_at end),
min(case when id = 'start_break' then created_at end)
) total_minutes
from (
select t.*, sum(activity = 'start_break') over(partition by employee_id order by id) grp
from mytable t
)
group by employee_id, grp
对于每次开始,您都可以使用窗口功能获得下一个结束:
select employee_id, time, created_at as start_time, end_time,
timestamp_diff(second, start_time, end_time)
from (select t.*,
min(case when activity = 'end_break' then created_at end) over (partition by employee_id order by created_at desc) as end_time
from t
) t
where activity = 'start_break';
Select id, min(activity='start_break')
Over (partition by id<=id%2),
Min(activity='end_break')Over
(partition by id<=id%2),
Min(Case when
activity='end_break' then
Date end) - Min(Case when
activity='start_break' then
Date end)Over (partition by
id<=id%2)
具有自我加入:
select c1.employee_id,
c1.created_at `start`, min(c2.created_at) `end`,
time_format(timediff(
min(c2.created_at),
c1.created_at
), "%H:%i") total
from clock_activities c1 inner join clock_activities c2
on c1.employee_id = c2.employee_id
and c1.activity = 'start_break' and c2.activity = 'end_break'
and c1.created_at < c2.created_at
group by c1.employee_id, c1.created_at
请参见demo。结果:
| employee_id | start | end | total |
| ----------- | ----- | ---- | ----- |
| 1 | 1:00 | 1:10 | 00:10 |
| 1 | 2:00 | 2:10 | 00:10 |
| 1 | 2:30 | 2:45 | 00:15 |
| 1 | 3:10 | 3:20 | 00:10 |