我有这样的字典:
dic = {'a':[['1'],['4']],'b':['1'],'c':['2']}
并且我想删除不必要的列表以获取:
newdict={'a':['1','4'],'b':'1','c':'2'}
我该怎么做?谢谢!
好吧,如果您不关心速度或效率,我想这可能有效:
def flatten(l):
output = []
for element in l:
if type(element) == list:
output.extend(flatten(element))
else:
output.append(element)
return output
dic = {'a':[[[['1'],['4']]],'3'],'b':['1'],'c':['2']}
newdict = {key: flatten(value) for key, value in dic.items()}
print(newdict)
如预期般给予:
{'a': ['1', '4', '3'], 'b': ['1'], 'c': ['2']}