如何将以逗号和空格分隔的整数读取为二维数组？

Question

我有一个看起来像这样的输入文件：

3, 2, 5
2, 4, 9
6, 5, 9

而且我做了array[3][3]。

我的问题是：如何在跳过空格和逗号的同时将其读入数组？

[另外：我不能使用stoi（没有C ++ 11），而且我还没有介绍向量。

我已经尝试过下面的代码块，但是我得到的数组充满了零。

    string sNum;                     // Current number (as string)
    int num = 0;                     // Current number (as int)
    ifstream inFile;                 // Make input file stream
    inFile.open("Numbers.txt");      // Open my input file of 3x3 numbers

     while (getline(inFile, sNum, ',')) {                                 // Gets 'line' from infile ..
                                                                             // puts it in sNum .. 
                                                                             // delimiter is comma (the problem?).
        for (int rowCount=0; rowCount<3; rowCount++) {                    // Go through the rows
                for (int columnCount=0; columnCount<3; columnCount++) {   // Go through the columns

                        num = atoi(sNum.c_str());                         // String 'sNum' to int 'num'
                        array[rowCount][columnCount] = num;               // Put 'num' in array


                } // end columnCount for
        } // end rowCount for
    } // end while

我认为这是在空间中阅读。如何忽略获取整数之间的间隔？

Answer 1

这里是一个解决方案：

string sNum;                     // Current number (as string)                                                                                                                                                  
int array[3][3];
int num = 0;                     // Current number (as int)                                                                                                                                                     
    ifstream inFile;                 // Make input file stream                                                                                                                                                  
    stringstream ss;
    inFile.open("Numbers.txt");      // Open my input file of 3x3 numbers                                                                                                                                       
    int row = 0;
    int col = 0;
     while (getline(inFile, sNum)) {                                 // Gets 'line' from infile ..                                                                                                              
        ss.str(sNum);

        while(ss >> num)
        {
           if(col == 3)
           {
              row++;
              col = 0;
           }

           cout << num << " ";;
           array[row][col] = num;
           col++;
           while(ss.peek() == ',' || ss.peek() == ' ')
              ss.ignore();
        }
        ss.clear();
     } //        end while                                                                                                                                                                                      

}

Answer 2

删除两个for循环，它们不是必需的。试试这个：

string sNum;                     // Current number (as string)
int num = 0;                     // Current number (as int)
ifstream inFile;                 // Make input file stream
inFile.open("numbers.txt");      // Open my input file of 3x3 numbers

int rowCount = 0;
int columnCount = 0;
while (getline(inFile, sNum, ',')) {                                 // Gets 'line' from infile ..
    num = atoi(sNum.c_str());                         // String 'sNum' to int 'num'
    iArray[rowCount][columnCount] = num;               // Put 'num' in array
    columnCount += 1; if (columnCount > 2) { columnCount = 0; rowCount += 1; }
} // end while

for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
        cout << iArray[i][j];
    }
    cout << '\n';
}