骰子滚动模拟器

Question

我正在用python制作骰子滚动模拟器来播放dnd。我是python的新手，所以如果我的代码真的很糟糕，请不要取笑我。

import random
while 1 == 1:
    dice = input("What kind of dice would you like to roll?: ") # This is asking what kind of dice to roll (d20, d12, d10, etc.)
    number = int(input("How many times?: ")) # This is the number of times that the program will roll the dice
    if dice == 'd20':
        print(random.randint(1,21) * number)
    elif dice == 'd12':
        print(random.randint(1,13) * number)
    elif dice == 'd10':
        print(random.randint(1,11) * number)
    elif dice == 'd8':
        print(random.randint(1,9) * number)
    elif dice == 'd6':
        print(random.randint(1,7) * number)
    elif dice == 'd4':
        print(random.randint(1,5) * number)
    elif dice == 'd100':
        print(random.randint(1,101) * number)
    elif dice == 'help':
        print("d100, d20, d12, d10, d8, d6, d4, help, quit")
    elif dice == 'quit':
        break
    else:
        print("That's not an option. Type help to get a list of different commands.")

quit()

我最初的注意力只是顺其自然，而不是让数字可变，但是我的弟弟提醒我，有些武器具有多次掷骰，而不是仅仅多次掷骰，我想输入一个信息询问掷骰子。现在我的代码存在的问题是，它将数字随机化，然后then乘以2。我要它做的是乘以[[different整数的数量并将其相加。

Answer 1

也许使用for循环并在number上迭代用户想要掷骰子的次数，同时将这些骰子保存到列表中以显示骰子的每一卷。

例如，第一个骰子可能看起来像这样：

rolls = []
if dice == 'd20':
    for roll in range(number):
        rolls.append(random.randint(1,21))
    print('rolls: ', ', '.join([str(roll) for roll in rolls]))
    print('total:', sum(rolls))

示例输出：
What kind of dice would you like to roll?: d20
How many times?: 2
rolls:  10, 15
total: 25

Answer 2

import random

print("Rolling the Dice....")
dice_number = random.randint(1, 6)
print(dice_number)
limit = 0
while limit <= 4:

    ask = input("Would you like to roll again?? Yes or No ").upper()
    limit = limit + 1
    if ask == "YES":
        print(random.randint(1, 6))
    elif ask == "NO":
        print("Thank You.")
        break
    else:
        print("Thank You.")
        break
 else:
    print("Limit Reached..TRY AGAIN!!")