我正在尝试以编程方式通过 Whatsapp 发送消息，代码可以正常工作，但用户需要单击发送按钮。我需要该应用程序来完成所有操作（所有用户交互）。一种方法如下。
转到菜单按钮 > 设置 > 聊天。并选中“输入是发送选项”
这是我正在使用的代码：
protected void sendwts(){
String smsNumber = "2126123456789"; // E164 format without '+' sign
Intent sendIntent = new Intent(Intent.ACTION_SEND);
// Intent sendIntent = new Intent(Intent.ACTION_SENDTO);
sendIntent.setType("text/plain");
sendIntent.putExtra(Intent.EXTRA_TEXT, "test \n");
sendIntent.putExtra("jid", smsNumber + "@s.whatsapp.net"); //phone number without "+" prefix
sendIntent.setPackage("com.whatsapp");
startActivity(sendIntent);
}
谢谢你
您可以仅使用Android的Accessibility API来做到这一点。
这个想法很简单，你实际上会让 Android 执行 Whatsapp 发送按钮的点击操作。
所以流程将是：
Sent by MY_APPEditTextEditText这是一个示例（如果您想使其更具限制性，您可以对其进行调整）：
public class WhatsappAccessibilityService extends AccessibilityService {
@Override
public void onAccessibilityEvent (AccessibilityEvent event) {
if (getRootInActiveWindow () == null) {
return;
}
AccessibilityNodeInfoCompat rootInActiveWindow = AccessibilityNodeInfoCompat.wrap (getRootInActiveWindow ());
// Whatsapp Message EditText id
List<AccessibilityNodeInfoCompat> messageNodeList = rootInActiveWindow.findAccessibilityNodeInfosByViewId ("com.whatsapp:id/entry");
if (messageNodeList == null || messageNodeList.isEmpty ()) {
return;
}
// check if the whatsapp message EditText field is filled with text and ending with your suffix (explanation above)
AccessibilityNodeInfoCompat messageField = messageNodeList.get (0);
if (messageField.getText () == null || messageField.getText ().length () == 0
|| !messageField.getText ().toString ().endsWith (getApplicationContext ().getString (R.string.whatsapp_suffix))) { // So your service doesn't process any message, but the ones ending your apps suffix
return;
}
// Whatsapp send button id
List<AccessibilityNodeInfoCompat> sendMessageNodeInfoList = rootInActiveWindow.findAccessibilityNodeInfosByViewId ("com.whatsapp:id/send");
if (sendMessageNodeInfoList == null || sendMessageNodeInfoList.isEmpty ()) {
return;
}
AccessibilityNodeInfoCompat sendMessageButton = sendMessageNodeInfoList.get (0);
if (!sendMessageButton.isVisibleToUser ()) {
return;
}
// Now fire a click on the send button
sendMessageButton.performAction (AccessibilityNodeInfo.ACTION_CLICK);
// Now go back to your app by clicking on the Android back button twice:
// First one to leave the conversation screen
// Second one to leave whatsapp
try {
Thread.sleep (500); // hack for certain devices in which the immediate back click is too fast to handle
performGlobalAction (GLOBAL_ACTION_BACK);
Thread.sleep (500); // same hack as above
} catch (InterruptedException ignored) {}
performGlobalAction (GLOBAL_ACTION_BACK);
}
}
然后在
res -> xml -> whatsapp_service.xml<?xml version="1.0" encoding="utf-8"?>
<accessibility-service
xmlns:android="http://schemas.android.com/apk/res/android"
android:accessibilityEventTypes="typeWindowContentChanged"
android:packageNames="com.whatsapp"
android:accessibilityFeedbackType="feedbackSpoken"
android:notificationTimeout="100"
android:canRetrieveWindowContent="true"/>
然后在您的清单中声明它：
<service
android:name=".services.WhatsappAccessibilityService"
android:label="Accessibility Service"
android:permission="android.permission.BIND_ACCESSIBILITY_SERVICE">
<meta-data
android:name="android.accessibilityservice"
android:resource="@xml/whatsapp_service"/>
<intent-filter>
<action android:name="android.accessibilityservice.AccessibilityService"/>
</intent-filter>
</service>
最后一件事是检查您的应用程序是否启用了辅助服务，如果没有，请将用户重定向到设置：
private boolean isAccessibilityOn (Context context, Class<? extends AccessibilityService> clazz) {
int accessibilityEnabled = 0;
final String service = context.getPackageName () + "/" + clazz.getCanonicalName ();
try {
accessibilityEnabled = Settings.Secure.getInt (context.getApplicationContext ().getContentResolver (), Settings.Secure.ACCESSIBILITY_ENABLED);
} catch (Settings.SettingNotFoundException ignored) { }
TextUtils.SimpleStringSplitter colonSplitter = new TextUtils.SimpleStringSplitter (":");
if (accessibilityEnabled == 1) {
String settingValue = Settings.Secure.getString (context.getApplicationContext ().getContentResolver (), Settings.Secure.ENABLED_ACCESSIBILITY_SERVICES);
if (settingValue != null) {
colonSplitter.setString (settingValue);
while (colonSplitter.hasNext ()) {
String accessibilityService = colonSplitter.next ();
if (accessibilityService.equalsIgnoreCase (service)) {
return true;
}
}
}
}
return false;
}
您将使用以下方式拨打电话：
if (!isAccessibilityOn (context, WhatsappAccessibilityService.class)) {
Intent intent = new Intent (Settings.ACTION_ACCESSIBILITY_SETTINGS);
context.startActivity (intent);
}
这纯粹是解决方案的技术方面。
现在，道德问题“你应该这样做吗？”，我相信答案很明确：
除非您的目标人群是残疾人（这正是 Accessibility API 的目的），否则您应该不这样做。
@JayVDiyk，正如@Syed M. Sannan 所说，答案是肯定的。
@Harshal Benake，我也遇到了这个问题...所以，在 poc 中关于这个...我使用 try-catch 做了一个解决方法：
:
AccessibilityNodeInfoCompat rootInActiveWindow = AccessibilityNodeInfoCompat.wrap (getRootInActiveWindow ());
try {
<here is where the exception raises>
}catch (Exception e){ return; }
// Now go back to your app by clicking on the Android back button twice:
:
现在，在wap中发送消息后，返回应用程序不会失败。
非常感谢！ （我是 flutter 和 android 的新手......这很有趣，我学到了一些东西）