当继承的类型由属性标记时,如何获取继承类型而不是基类型?
我们可以用Ninject做到吗?这就是我所拥有的:
static void Main(string[] args)
{
IKernel kernel = new StandardKernel();
// use Method which return properly type
kernel.Bind<IBase>().ToMethod(context => SOMEMETHOD());
// should be return DerivedClass
BaseClass derived = kernel.Get<BaseClass>();
BaseClass1 derived1 = kernel.Get<BaseClass1>();
// The result should be:
derived.WhoIAm(); //--> "DerivedClass"
derived1.WhoIAm(); //--> "DerivedClass1"
}
// method which resolve this
static object SOMEMETHOD()
{
// return derived class wich marked by
// SomeAttribure where base class that which we use in kernel.Get
}
基础类
class BaseClass : IBase
{
public virtual void WhoIAm()
{
Console.Write(this.GetType());
}
}
class BaseClass1 : IBase
{
public virtual void WhoIAm()
{
Console.Write(this.GetType());
}
}
继承的类。 SomeAttribute
是一个标记应该创建的类型的属性
[SomeAttribute]
class DerivedClass : BaseClass
{
public override void WhoIAm()
{
Console.Write(this.GetType());
}
}
其他派生类继承自BaseClass1
[SomeAttribute]
class DerivedClass1 : BaseClass1
{
public override void WhoIAm()
{
Console.Write(this.GetType());
}
}
class SomeAttribute : Attribute {}
interface IBase
{
void WhoIAm();
}
查看约定扩展。应该是直截了当的。就像是
kernel.Bind(x =>
{
x.FromThisAssembly()
.SelectAllClasses()
.WithAttribute<SomeAttribute>()
.BindBase();
});