输出示例:
>Hello! Welcome to the day calculator Enter a month to check: (1-Jan, 2-Feb, etc) 2
>Enter day to check: 21
>Enter the weekday of the 1st of the month(1-Sunday, 2-Monday, etc) 5
>The 21.2 will be a Wednesday
我可以使用任何公式来缩短此代码吗?
由于没有给出年份,无法确定2月份是否会有28天或29天。所以,没有费心去处理错误的输入。如果你输入一些不可能的日期值而不是错误,你将得到错误的输出。
void main()
{
int month, day, date, first;
printf("enter the month\n");
scanf("%d",&month);
printf("enter the date\n");
scanf("%d",&date);
printf("enter the 1st day of the month\n");
scanf("%d",&first);
day = (date+first-2)%7;
if(day==0)
printf("sunday\n");
else if(day==1)
printf("monday\n");
else if(day==2)
printf("tuesday\n");
else if(day==3)
printf("wednesday\n");
else if(day==4)
printf("thursday\n");
else if(day==5)
printf("friday\n");
else
printf("saturday\n");
}