第一，我需要得到两个最长线长的两个方程
运行以下代码时
from sympy import *
import math
class shape():
def __init__(self,T):
self.T=T
self.Ax = self.T[0][0]
self.Ay = self.T[0][1]
self.Bx = self.T[1][0]
self.By = self.T[1][1]
self.Cx = self.T[2][0]
self.Cy = self.T[2][1]
#Triangle:
self.C_dashx = 0.5 * (self.Ax + self.Bx)
self.C_dashy = 0.5 * (self.Ay + self.By)
self.B_dashx = 0.5 * (self.Ax + self.Cx)
self.B_dashy = 0.5 * (self.Ay + self.Cy)
self.A_dashx = 0.5 * (self.Bx + self.Cx)
self.A_dashy = 0.5 * (self.By + self.Cy)
if (self.Ax - self.A_dashx) == 0:
self.m_AA =0
else:
self.m_AA = (self.Ay - self.A_dashy) / (self.Ax - self.A_dashx)
if (self.Bx - self.B_dashx) == 0:
self.m_BB =0
else:
self.m_BB = (self.By - self.B_dashy) / (self.Bx - self.B_dashx)
if (self.Bx - self.B_dashx) == 0:
self.m_CC =0
else:
self.m_CC = (self.Cy - self.C_dashy) / (self.Bx - self.B_dashx)
def triangle_intersection(self):
self.x , self.y = symbols('x y')
self.eq1=Eq(self.m_AA*(self.x-self.Ax)+self.Ay-self.y,0)
self.eq2=Eq(self.m_BB*(self.x-self.Bx)+self.By-self.y,0)
self.solve_equation=solve([self.eq1,self.eq2],[self.x,self.y])
self.Zx=(self.solve_equation[self.x]).factor()
self.Zy=(self.solve_equation[self.y]).factor()
print(self.Zx,self.Zy)
def square_intersection(self):
self.Dx = self.T[3][0]
self.Dy = self.T[3][0]
# Line Solpe:
if (self.Bx - self.Ax) == 0:
self.m_AB = 0
else:
self.m_AB = (self.By - self.Ay) / (self.Bx - self.Ax)
if (self.Dx - self.Ax) == 0:
self.m_AD = 0
else:
self.m_AD = (self.Dy - self.Ay) / (self.Dx - self.Ax)
if (self.Cx - self.Bx) == 0:
self.m_BC = 0
else:
self.m_BC = (self.Cy - self.By) / (self.Cx - self.Bx)
if (self.Dx - self.Bx) == 0:
self.m_BD = 0
else:
self.m_BD = (self.Dy - self.By) / (self.Dx - self.Bx)
if (self.Dx - self.Cx) == 0:
self.m_CD = 0
else:
self.m_CD = (self.Dy - self.Cy) / (self.Dx - self.Cx)
if (self.Cx - self.Ax) == 0:
self.m_AC = 0
else:
self.m_AC = (self.Cy - self.Ay) / (self.Cx - self.Ax)
# Equation:
#### WHAT IS PROBLEM HERE###########
self.z, self.t = symbols('z t',positive=True)
self.eq_AB = Eq(self.m_AB * (self.z - self.Ax) + self.Ay - self.t,0)
self.eq_AC = Eq(self.m_AC * (self.z - self.Ax) + self.Ay - self.t,0)
self.eq_AD = Eq(self.m_AD * (self.z - self.Ax) + self.Ay - self.t,0)
self.eq_BC = Eq(self.m_BC * (self.z - self.Bx) + self.By - self.t,0)
self.eq_BD = Eq(self.m_BD * (self.z - self.Bx) + self.By - self.t,0)
self.eq_CD = Eq(self.m_CD * (self.z - self.Cx) + self.Cy - self.t,0)
self.length_AB = math.sqrt((self.Bx - self.Ax)**2 + (self.By - self.Ay)**2)
self.length_AC = math.sqrt((self.Cx - self.Ax)**2 + (self.Cy - self.Ay)**2)
self.length_AD = math.sqrt((self.Dx - self.Ax)**2 + (self.Dy - self.Ay)**2)
self.length_BC = math.sqrt((self.Cx - self.Bx)**2 + (self.Cy - self.By)**2)
self.length_BD = math.sqrt((self.Dx - self.Bx)**2 + (self.Dy - self.By)**2)
self.length_CD = math.sqrt((self.Dx - self.Cx)**2 + (self.Dy - self.Cy)**2)
#### WHAT IS PROBLEM HERE###########
self.lenghts = [(self.length_AB, self.eq_AB),(self.length_AC, self.eq_AC),(self.length_AD, self.eq_AD),(self.length_BC, self.eq_BC)
, (self.length_BD, self.eq_BD), (self.length_CD, self.eq_CD)]
self.newlenghts = sorted(self.lenghts,reverse=True)
self.max1=self.newlenghts[0][1]
self.max2=self.newlenghts[1][1]
self.solve_equation_sq = solve([self.max1, self.max2], [self.z, self.t])
print(self.solve_equation_sq)
self.Rx = (self.solve_equation_sq[self.z]).factor()
self.Ry = (self.solve_equation_sq[self.t]).factor()
print(self.Rx, self.Ry)
test=[(0,0),(4,0),(4,4),(0,4)]
a1=shape(test)
a1.triangle_intersection()
a1.square_intersection()
我收到以下错误
2.66666666666667 1.33333333333333{z：t}追溯（最近一次通话）：文件“ C：/Users/xxxxx/.PyCharmCE2019.3/config/scratches/programme逻辑函数.py”，第127行，在>
a1.square_intersection()文件“ C：/Users/xxxxx/.PyCharmCE2019.3/config/scratches/programme逻辑函数.py”，第119行，在square_intersection中
self.Ry = (self.solve_equation_sq[self.t]).factor()KeyError：t
第一，我需要得到两个最长线长的两个方程，我把带有等式的长度放在列表中，像这样[[length 1，eq 1），.....]反向排序列表得到两个最长线的两个方程...
如果打印出要求解的方程，您将看到它们相同，因此返回的唯一解是{z:t}而不是{z:smthng, t:smthngelse}。因此，当您请求t的值时，它将告诉您解决方案字典中没有t。现在，您必须返回并看到已正确计算了要求解的方程。