在Django REST Framework中使用url传递查询

问题描述 投票:0回答:2

我觉得这应该很简单,但我正在做的事情并没有得到回报。

在Django中,我在我的应用程序中有这个urls.py:

from django.urls import path

from .views import PostcodessAPIListView, PostcodesAPIID, PostcodesWithinRadius

urlpatterns = [
    path("<str:postcode>/<int:radius_km>", PostcodesWithinRadius.as_view(), name="results_api_radius"),
    path("", PostcodessAPIListView.as_view(), name="results_api_list"),
    path("<int:pk>", PostcodesAPIID.as_view(), name="results_api_detail"),
]

我有这个观点,应该采用邮政编码和半径为km,调用外部api将邮政编码转换为经度和纬度,然后再次调用外部api以获得一定范围内的邮政编码。

class PostcodesWithinRadius(generics.RetrieveAPIView):
    serializer_class = PostcodeSerializer

    def get_queryset(self):
        postcode = self.request.query_params.get('postcode', None)
        radius_km = self.request.query_params.get('radius_km', None)
        print(postcode, radius_km)
        postcodes = self.get_postcodes_within_radius(postcode, radius_km)
        print(postcodes)
        return Postcode.objects.filter(postcode__in=postcodes)

    def get_postcodes_within_radius(self, postcode, radius_km):

        radius_km = 3
        postcodes_within_radius = []

        if radius_km <= 20:
            radius = radius_km * 1000
        else:
            raise ValueError('Radius cannot be over 20km.')

        GET_LAT_LON_URL = f"{POSTCODE_URL}?"

        postcode_query = {
            "query": postcode
        }

        postcode_data = requests.get(GET_LAT_LON_URL, headers=None, params=postcode_query).json()
        print(postcode_data)
        querystring = {
            "longitude": postcode_data['result'][0]['longitude'],
            "latitude": postcode_data['result'][0]['latitude'],
            "wideSearch": radius,
            "limit": 100,
        }

        res = requests.get(POSTCODE_URL, headers=None, params=querystring).json()


        for postcode in res['result']:
            postcodes_within_radius.append(postcode['postcode'])
        return postcodes_within_radius

但是,邮政编码和半径没有通过网址参数传递 - 是什么给出的?

django parameters django-rest-framework django-urls
2个回答
1
投票

你没有传递postcoderadius作为query参数,而是作为url参数。

如果你的url是这样的,那么你的方法就可以了:

http://localhost:8000/postcodes/?postcode=0000&radius=5

但是因为你正在使用url参数:

http://localhost:8000/<postcode>/<radius>

你需要改变你的get_queryset方法。试试这个:

def get_queryset(self):
    postcode = self.kwargs.get('postcode', None)
    radius_km = self.kwargs.get('radius_km', None)
    print(postcode, radius_km)
    postcodes = self.get_postcodes_within_radius(postcode, radius_km)
    print(postcodes)
    return Postcode.objects.filter(postcode__in=postcodes)

0
投票

为什么你不使用get()方法

class PostcodesWithinRadius(generics.RetrieveAPIView):
    serializer_class = PostcodeSerializer

    def get(self, request, **kwargs):
        postcode = kwargs.get('postcode')
        radius_km = kwargs.get('radius_km')
        # rest of the logic 
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