在列表视图位置编辑项目

问题描述 投票:0回答:1

嗨,我是一个新的Android开发者。我试图改变一些元素在我的项目上一次点击,这是我的代码

ListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
                ImageView img = findViewById(R.id.imageView2);
                img.setImageResource(R.drawable.validate);
                TextView txtNumTicket, txtCaisse;
                txtNumTicket = findViewById(R.id.ref);
                txtCaisse = findViewById(R.id.textView);
                txtNumTicket.setTextColor(ContextCompat.getColor(Commande.this, R.color.bon));
                txtCaisse.setTextColor(ContextCompat.getColor(Commande.this, R.color.bon));
                Toast.makeText(getApplicationContext(), "You have selected item no."
                        + (i + 1) + "", Toast.LENGTH_SHORT).show();

            }
        });

我想恢复到初始状态(改变形象R.id.novalidate和颜色的TextView)位置时,等于6,我该怎么办呢?

android android-listview
1个回答
0
投票

评论后更新:

if (yourListView.getAdapter().getCount()  == 6) {
    img.setImageResource(R.drawable.novalidate);
    txtNumTicket.setTextColor(ContextCompat.getColor(Commande.this, R.color.your_new_colour));
    txtCaisse.setTextColor(ContextCompat.getColor(Commande.this, R.color.your_new_colour));
}

2ndUPDATE:基于this answer,这里就是你可以在你的列表中的特定位置获得一个视图

public View getViewByPosition(int pos, ListView listView) {
    final int firstListItemPosition = listView.getFirstVisiblePosition();
    final int lastListItemPosition = firstListItemPosition + listView.getChildCount() - 1;

    if (pos < firstListItemPosition || pos > lastListItemPosition ) {
        return listView.getAdapter().getView(pos, null, listView);
    } else {
        final int childIndex = pos - firstListItemPosition;
        return listView.getChildAt(childIndex);
    }
}

所以,你可以得到你想要通过调用视图:

View view = getViewByPosition (number_of_the_view_you_want_to_change, name_of_your_listview);

然后结合该项目的textviews / imageviews(view.findViewById(...)),并如上所述设置的颜色和文本

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