数字转到下一个空单元格？

Question

For some reason this script doesn't go to the next empty cell in column?  

我做错了什么？ 我希望能够将今天的日期添加到列中的下一个空单元格中 如果这些数字不会改变但保持在那个日期，那就太好了

需要一些帮助 预先感谢。

on run {input, parameters}
	
	tell application "Numbers"
		activate
		tell the first table of the active sheet of document 1
			tell column "F"
				set r to (address of row of last cell whose value is greater than "")
				set r to r + 1
				set value of cell r to date string of (current date)
			end tell
		end tell
	end tell
	
	
	return input
end run

Answer 1

这是我用来查找列中下一个空单元格的代码：

tell application "Numbers"
    tell front document
        tell table 1 of sheet 1
            set fullSheet to 1
            repeat
                set cellValue to value of cell ("A" & fullSheet) --of table 1 of sheet 1
                if cellValue = missing value then exit repeat
                set fullSheet to fullSheet + 1
            end repeat
        end tell
    end tell
end tell

我知道它不是很迷人，但自 2014 年 2 月以来，它一直在所有数字升级中发挥作用。

Answer 2

我不确定为什么脚本中的选择器不起作用，但我需要做同样的事情并想出了这种方法；我使用错误捕获来覆盖没有行为空的情况

tell application "Numbers"
  tell table 1 of active sheet of front document
    tell column "A"
      try
        set the_cell to first cell whose value is missing value
      on error -- no empty cell in this column, need to add row
        add row below last row
        set the_cell to cell (count of rows)
      end try
      set value of the_cell to current date
      
      -- get row number in case need to set values in other columns
      set the_row to address of row of the_cell
    end tell
  end tell
end tell