node.js-使用存档器存档文件夹会生成一个空的zip

Question

我正在尝试使用archiver归档文件夹，我要归档的文件夹路径如下所示：

tmp
   |
    folderToArchive
        │file1.txt 
        │file2.txt 
        │file3.txt 

将在其中生成zip文件的服务器端代码如下：

var archiver = require("archiver");

    app.get("/download/:folder", (req, res) => {

      var FolderName = req.params.folder;
      var zipName = FolderName + ".zip";
      var source = path.join(__dirname, "tmp", FolderName);
      var out = path.join(__dirname, "tmp", zipName);


      const archive = archiver('zip', { zlib: { level: 9 }});
      const stream = fs.createWriteStream(out);

      return new Promise((resolve, reject) => {
        archive
          .directory(source, false)
          .on('error', err => reject(err))
          .pipe(stream)
        ;

        stream.on('close', () => resolve());
        archive.finalize();
        console.log("zip file created");
      });

    });

问题是，当我运行该应用程序时，它将在正确的目标位置创建一个空的zip文件。

这对我来说是全新的，我想了解为什么zip文件为空？

问候

Answer 1

var source = path.join(__dirname, "tmp", FolderName);
var out = path.join(__dirname, "tmp", zipName);

路径相对于正在运行的.js文件。为了

/tmp/folderToArchive/*.text 

或

tmp
   |
    folderToArchive
        │file1.txt 
        │file2.txt 
        │file3.txt 

您需要将其更改为：

var source = path.join("/tmp", FolderName);
var out = path.join("/tmp", zipName);

此外，也不需要承诺：

app.get("/download/:folder", (req, res) => {

  var FolderName = req.params.folder;
  var zipName = FolderName + ".zip";
  var source = path.join("/tmp", FolderName);
  var out = path.join("/tmp", zipName);


  const archive = archiver('zip', { zlib: { level: 9 }});
  const stream = fs.createWriteStream(out);

  archive
      .directory(source, false)
      .on('error', err => {throw err;})
      .pipe(stream);

  stream.on('close', () => console.log("closed"));
  archive.finalize();
  console.log("zip file created");

});