typescript并与层次结构绑定

Question

我尝试创建绑定层次结构，以便我可以轻松地构建一些预定义的操作。似乎Action函数出了问题，因为它在绑定时并没有真正起作用。

const Action = (channel: string) => {
    return (action: string) => {
        return (payload: object) => {
            return Object.assign({},payload,{channel: channel, action: action});
        };
    };
};

const WeatherAction = Action.bind('weather');
const WeatherActionSub = WeatherAction.bind('sub');
const WeatherActionUnSub = WeatherAction.bind('unsub');

const test = WeatherActionSub({test: 'test'});
console.log(test);

https://jsfiddle.net/cvowrj0y/

Answer 1

Bind的第一个参数改变了this关键字。你只需要在这里打电话，因为这个功能无论如何：

const WeatherAction = Action('weather');
const WeatherActionSub = WeatherAction('sub');
const WeatherActionUnSub = WeatherAction('unsub');

const test = WeatherActionSub({test: 'test'});
console.log(test);

---

（有效的绑定代码，这是毫无意义的，因为没有参数的调用必须遵循:)

const WeatherAction = Action.bind(null, 'weather')();
const WeatherActionSub = WeatherAction.bind(null, 'sub')();
const WeatherActionUnSub = WeatherAction.bind(null, 'unsub')();

如果函数未被破坏，那么绑定是有意义的：

const ActionUncurried = (channel: string, action: string, payload: object) => {
    return Object.assign({},payload,{channel: channel, action: action});
};

const WeatherAction = ActionUncurried.bind(null, 'weather');
const WeatherActionSub = WeatherAction.bind(null, 'sub');
const WeatherActionUnSub = WeatherAction.bind(null, 'unsub');

const test = WeatherActionSub({test: 'test'});
console.log(test);