我该怎么办形成笨验证,如果我不想刷新页面?基本上,我这样做:
$config = array(
array(
'field' => 'c_name',
'label' => 'Name',
'rules' => 'trim|required'
),
array(
'field' => 'c_job',
'label' => 'Job',
'rules' => 'trim|required',
)
);
$this->form_validation->set_rules($config);
if($this->form_validation->run() == true)
{
$this->load->model('model');
//.....
}
else{
$this->load->view('view');
}
但是,如果我用Ajax发送数据和网页不刷新,我该怎么办表单验证?
编辑:
感谢@阿姆拉Kojon。这是好作品,但新的问题是这样的:
if ($this->form_validation->run() == FALSE) {
echo validation_errors();
}
else {
//echo 'hi';
$value = $this->input->post('value');
$values = array(
'c_name' => $value['c_name'],
'c_job'=> $value['c_job'],
'c_address'=> $value['c_address'],
'c_phone'=> $value['c_phone'],
'c_mail'=> $value['c_mail'],
'c_state'=> $value['c_state'],
'c_intrest'=> $value['c_intrest'],
'c_added_info'=> $value['c_added_info']
);
$add = $this->customers_model->add_customer($values);
echo $add;
}
如果我刚才说的回声在其他部分“东西”,它的工作原理,如果确认是好的,它呼应喜,但如果我写数据库主题(其值数组数据,并没有阿贾克斯的方式,将其插入日期),它不工作,else部分不能正常工作!
如果你给你的JS-的jQuery Ajax代码会更有效地理解您的问题。不要担心!我尝试下面的指令......
1)获取的形式获得价值,并通过形成如
<script type="text/javascript">
$(document).ready(function(){
var dataString = $("#FormId").serialize();
var url="ControllerName/MethodName"
$.ajax({
type:"POST",
url:"<?php echo base_url() ?>"+url,
data:dataString,
success:function (data) {
alert(data);
}
});
})
</script>
控制器:
function MethodName {
$this->form_validation->set_error_delimiters('', '');
$this->form_validation->set_rules('fname','First Name', 'required');
$this->form_validation->set_rules('lname','Last Name', 'required');
$this->form_validation->set_rules('email','Email Address','required|valid_email|is_unique[sec_users.email]');
if ($this->form_validation->run() == FALSE) {
echo validation_errors();
}
else {
// To who are you wanting with input value such to insert as
$data['frist_name']=$this->input->post('fname');
$data['last_name']=$this->input->post('lname');
$data['user_name']=$this->input->post('email');
// Then pass $data to Modal to insert bla bla!!
}
}希望,因为它是在我的应用程序中工作会工作。
请接受,如果它是最好的答案。
谢谢!
我知道你的问题是一岁,但你可以用这个使用CodeIgniter的最新引导
<?php
class Yourcontroller extends CI_Controller {
public function __construct() {
parent::__construct();
$this->load->library('form_validation');
}
public function index() {
$this->load->view('template/register');
}
public function validate() {
$json = array();
$this->form_validation->set_rules('username', 'Username', 'required');
$this->form_validation->set_rules('email', 'Email', 'trim|required|valid_email');
$this->form_validation->set_rules('password', 'Password', 'required|min_length[5]');
$this->form_validation->set_rules('confirm_password', 'Confirm Password', 'required|matches[password]');
$this->form_validation->set_rules('code', 'Login Code', 'required|numeric|min_length[4]||max_length[8]');
$this->form_validation->set_message('required', 'You missed the input {field}!');
if (!$this->form_validation->run()) {
$json = array(
'username' => form_error('username', '<p class="mt-3 text-danger">', '</p>'),
'email' => form_error('email', '<p class="mt-3 text-danger">', '</p>'),
'password' => form_error('password', '<p class="mt-3 text-danger">', '</p>'),
'confirm_password' => form_error('confirm_password', '<p class="mt-3 text-danger">', '</p>'),
'code' => form_error('code', '<p class="mt-3 text-danger">', '</p>')
);
}
$this->output
->set_content_type('application/json')
->set_output(json_encode($json));
}
}
阿贾克斯脚本
<script type="text/javascript">
$( document ).ready(function() {
$('#error').html(" ");
$('#form-submit-button').on('click', function (e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "<?php echo site_url('yourcontroller/validate');?>",
data: $("#form").serialize(),
dataType: "json",
success: function(data){
$.each(data, function(key, value) {
$('#input-' + key).addClass('is-invalid');
$('#input-' + key).parents('.form-group').find('#error').html(value);
});
}
});
});
$('#form input').on('keyup', function () {
$(this).removeClass('is-invalid').addClass('is-valid');
$(this).parents('.form-group').find('#error').html(" ");
});
});
</script>
完整视图代码
<div class="container">
<div class="row">
<div class="col-sm-6 ml-auto mr-auto m-auto">
<div class="card mt-5">
<h5 class="card-header"></h5>
<div class="card-body">
<?php echo form_open('agent/register', array('id' => 'form', 'role' => 'form'));?>
<div class="row">
<div class="col-sm-12">
<div class="form-group">
<?php echo form_input('username', '', array('class' => 'form-control', 'placeholder' => 'Enter Agent Username', 'id' => 'input-username'));?>
<div id="error"></div>
</div>
<hr/>
</div>
</div>
<div class="row">
<div class="col-sm-12">
<div class="form-group">
<?php echo form_input('email', '', array('class' => 'form-control', 'placeholder' => 'Enter Agent Email', 'id' => 'input-email'));?>
<div id="error"></div>
</div>
<hr/>
</div>
</div>
<div class="row">
<div class="col-sm-6">
<div class="form-group">
<?php echo form_password('password', '', array('class' => 'form-control', 'placeholder' => 'Enter Password', 'id' => 'input-password'));?>
<div id="error"></div>
</div>
<hr/>
</div>
<div class="col-sm-6">
<div class="form-group">
<?php echo form_password('confirm_password', '', array('class' => 'form-control', 'placeholder' => 'Enter Confirm Password', 'id' => 'input-confirm_password'));?>
<div id="error"></div>
</div>
<hr/>
</div>
</div>
<hr/>
<div class="row">
<div class="col-sm-12">
<div class="form-group">
<button type="button" class="btn btn-block btn-dark" id="form-submit-button">Register Agent</button>
</div>
</div>
</div>
<?php echo form_close();?>
</div>
</div>
</div>
</div>
</div>
<script type="text/javascript">
$( document ).ready(function() {
$('#error').html(" ");
$('#form-submit-button').on('click', function (e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "<?php echo site_url('yourcontroller/validate');?>",
data: $("#form").serialize(),
dataType: "json",
success: function(data){
$.each(data, function(key, value) {
$('#input-' + key).addClass('is-invalid');
$('#input-' + key).parents('.form-group').find('#error').html(value);
});
}
});
});
$('#agent-register-form input').on('keyup', function () {
$(this).removeClass('is-invalid').addClass('is-valid');
$(this).parents('.form-group').find('#error').html(" ");
});
});
</script>
如果您知道有关传递数据与阿贾克斯,则工作流程如下。
1)通过Ajax将表单数据发送到控制器。
2)不要表单验证,截至目前。
3)如果成功,然后“回声”值1
4)如果失败,回波值0
因此,使用回声值,就可以判断验证是否失败。我可以给你举个例子,如果你需要
示例Ajax代码
$('#form').on('submit', function(e){
e.preventDefault();
var data = $(this).serialize();
$.ajax({
url: 'your url',
type: 'POST',
data: data,
success: function(data){
if(data == 1){
$('#form')[0].reset();
alret('success');
}
else if(data == 0){
alret('failed');
}
},
error: function(){
alert('error');
}
});
});
Create MY_Form_validation in libraries folder
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class MY_Form_validation extends CI_Form_validation {
private $json = array();
private $opts = array();
function get_json($extra_array = array(),$error_array=array())
{
if(count($extra_array)) {
foreach($extra_array as $addition_key=>$addition_value) {
$this->json[$addition_key] = $addition_value;
}
}
$this->json['options'] = $this->opts;
if(!empty($error_array)){
foreach($error_array AS $key => $row)
$error[] = array('field' => $key, 'error' => $row);
}
foreach($this->_error_array AS $key => $row)
$error[] = array('field' => $key, 'error' => $row);
if(isset($error)) {
$this->json['status'] = 'error';
$this->json['errorfields'] = $error;
} else {
$this->json['status'] = 'success';
}
return json_encode($this->json);
}
}
Call this function in controller if validation failed:
echo $this->form_validation->get_json();
You get the response with form fieldname and errormessage
Example:
{"options":[],"status":"error","errorfields":[{"field":"email","error":"The Mobile Number\/Email\/Username field is required."},{"field":"password","error":"The Password field is required."}]}
试试这是我的工作(笨3.0)基本的例子,以达到你想要做什么
包括在你看来filename.js
document.getElementById("yourForm").reset();
$(document).ready( function() {
var yourForm = $('#yourForm');
yourForm.submit( function(event) {
event.preventDefault();
$.ajax( {
type: 'POST',
url: yourForm.attr( 'action' ),
data: yourForm.serialize(),
success: function(data) {
if (data.code == '200') {
$('#message').html(data.message);
document.getElementById("yourForm").reset();
}
},
error: function(data) {
var response = data.responseText;
var obj = jQuery.parseJSON(response);
if (obj.code == '500') {
var i;
for (i = 0; i < obj.field.length; i++) {
name = obj.field[i];
$('.label-'+name).addClass('label-error');
errors = JSON.stringify(obj.validation);
validate = jQuery.parseJSON(errors);
$('.helper-'+name).html(validate[name]);
}
}
}
} );
} );
} );
查看HTML形式例如在使用的className可以使用ID这个例子时以及改变filename.js相应文件
<form id="yourForm" action="base_url/controller/function_name" action="POST">
// Important text after className "label-" & "helper-" must be input name
<label class="label-firstName">Name</label>
<input type="text" name="firstName" />
<span class="helper-firstName"></span>
</form>
<div id="message"></div>
控制器PHP代码
public function function_name()
{
if(!empty($_POST)) {
$this->load->library('form_validation');
$this->form_validation->set_rules('firstName','First Name','required|max_length[16]');
if($this->form_validation->run())
{
$params = array(
'firstName' => $this->input->post('firstName'),
);
// Model returning $data['newRecord'] with $params and insertId
$data['newRecord'] = $this->Record_model->newRecord($params);
$reply = array();
$reply['code'] = 200;
$reply['record'] = array(
'insertId' => $data['newRecord']['insertId'],
'firstName' => $data['newRecord']['firstName']
);
$reply['message'] = 'Hello, ' .$data['newRecord']['firstName']. ' - We have received your message. ' .$data['newRecord']['insertId']. ' is your reference ID, for this communication.';
header('Content-Type: application/json; charset=UTF-8');
print json_encode($reply);
}
else {
$validation = $this->form_validation->error_array();
$field = array();
foreach($validation as $key => $value) {
array_push($field,$key);
}
$reply = array(
'code' => 500,
'field' => $field,
'validation' => $validation,
'message' => 'Submission failed due to validation error.'
);
header($_SERVER['SERVER_PROTOCOL'] . ' 500 Internal Server Problem', true, 500);
header('Content-Type: application/json; charset=UTF-8');
print json_encode($reply);
}
}
else {
$reply = array();
$reply['code'] = 403;
$reply['message'] = 'No Direct Access Allowed.';
header($_SERVER['SERVER_PROTOCOL'] . ' 403 Forbidden', true, 403);
header('Content-Type: application/json; charset=UTF-8');
print json_encode($reply);
}
}
如果使用AJAX,......你不能使用form_validation库这样你就可以在客户端使用jQuery验证...并在服务器端应该使用if语句来检查提交的数据