我有一个文件，其中包含测量的观察时间（时间和日期）。
输入文件：
TimeStamp=Wednesday,February 21,2018 4:33:10 PM
1,16.00,17.11,703.41,257.462,12.3,13.8
2,17.11,18.30,753.61,308.084,13.8,15.3
3,18.30,19.58,733.57,335.605,15.3,18.0
TimeStamp=Wednesday,February 21,2018 4:35:54 PM
1,16.00,17.11,638.19,233.251,12.3,13.5
2,17.11,18.30,606.43,247.558,13.5,15.5
3,18.30,19.58,708.14,323.502,15.5,18.2
TimeStamp=Wednesday,February 21,2018 4:38:37 PM
1,16.00,17.11,543.10,201.339,12.5,13.5
2,17.11,18.30,542.06,224.449,13.5,15.3
3,18.30,19.58,693.38,321.293,15.3,17.8
我想将月份名称转换为特定行的月号，其中包含“TimeStamps =”。此外，我还想将时间从12小时格式更改为24小时格式。
输出文件：
TimeStamp=Wednesday,02 21,2018 16:33:10
1,16.00,17.11,703.41,257.462,12.3,13.8
2,17.11,18.30,753.61,308.084,13.8,15.3
3,18.30,19.58,733.57,335.605,15.3,18.0
TimeStamp=Wednesday,02 21,2018 16:35:54
1,16.00,17.11,638.19,233.251,12.3,13.5
2,17.11,18.30,606.43,247.558,13.5,15.5
3,18.30,19.58,708.14,323.502,15.5,18.2
TimeStamp=Wednesday,02 21,2018 16:38:37
1,16.00,17.11,543.10,201.339,12.5,13.5
2,17.11,18.30,542.06,224.449,13.5,15.3
3,18.30,19.58,693.38,321.293,15.3,17.8
请帮忙。
先感谢您。
在sed脚本之后，可能是一个开始，可以根据输入进行改进或修复：
/^TimeStamp=/ {
s/January/01/
s/February/02/
s/March/03/
s/April/04/
s/May/05/
s/June/06/
s/July/07/
s/August/08/
s/September/09/
s/October/10/
s/November/11/
s/December/12/
/ PM *$/ {
s/ PM *$//
s/ 1:/ 13:/
s/ 2:/ 14:/
s/ 3:/ 15:/
s/ 4:/ 16:/
s/ 5:/ 17:/
s/ 6:/ 18:/
s/ 7:/ 19:/
s/ 8:/ 20:/
s/ 9:/ 21:/
s/ 10:/ 22:/
s/ 11:/ 23:/
}
/ AM *$/ {
s/ AM *$//
s/ 12:/ 0:/
}
}
sed命令
sed -f script_name < input_file > output_file
使用awk
$ awk -F "[, ]" ' /Time/{"date --date=\""$2" "$3" "$4"\" +%m" | getline m; "date --date=\""$5" "$6"\" +%T" | getline t; printf("%s,%02d %d,%d %s\n",$1,m,$3,$4,t); next}1' file
TimeStamp=Wednesday,02 21,2018 16:33:10
1,16.00,17.11,703.41,257.462,12.3,13.8
2,17.11,18.30,753.61,308.084,13.8,15.3
3,18.30,19.58,733.57,335.605,15.3,18.0
TimeStamp=Wednesday,02 21,2018 16:35:54
1,16.00,17.11,638.19,233.251,12.3,13.5
2,17.11,18.30,606.43,247.558,13.5,15.5
3,18.30,19.58,708.14,323.502,15.5,18.2
TimeStamp=Wednesday,02 21,2018 16:38:37
1,16.00,17.11,543.10,201.339,12.5,13.5
2,17.11,18.30,542.06,224.449,13.5,15.3
3,18.30,19.58,693.38,321.293,15.3,17.8
我们在qazxsw poi中调用qazxsw poi
date：在日期命令和月份整数结果中传递必填字段将在awk中存储
"date --date=\""$2" "$3" "$4"\" +%m" | getline m;：类似的m将有24小时格式的时间
"date --date=\""$5" "$6"\" +%T" | getline t;扩展的t解决方案：
@echo off
setlocal EnableDelayedExpansion
set /A i=100, AM=0, PM=12
for %%a in (January February March April May June July August September October November December) do (
set /A i+=1
set "month[%%a]=!i:~1!"
)
(for /F "delims=" %%l in (input.txt) do (
set "line=%%l"
if "!line:~0,4!" equ "Time" (
for /F "tokens=1-8 delims=,: " %%a in ("%%l") do (
set /A hour=%%e+%%h
set "line=%%a,!month[%%b]! %%c,%%d !hour!:%%f:%%g"
)
)
echo !line!
)) > output.txt
输出：
awkawk 'BEGIN{
split("Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec", month);
for (i in month) months[month[i]] = sprintf("%02d", i);
FS = OFS = ","
}
/TimeStamp/{
sub(/^[^[:space:]]+/, months[substr($2, 1, 3)], $2);
split($3, t, " ");
h=sprintf("%02d", substr(t[2], 1, length(t[2])==8? 2 : 1) + (t[3]=="PM"? 12 : 0));
if (h == 24) h="00";
sub(/^[0-9]+/, h, t[2]);
$3 = t[1]" "t[2]
}1' file
救援！ （使用系统日期）
TimeStamp=Wednesday,02 21,2018 16:33:10
1,16.00,17.11,703.41,257.462,12.3,13.8
2,17.11,18.30,753.61,308.084,13.8,15.3
3,18.30,19.58,733.57,335.605,15.3,18.0
TimeStamp=Wednesday,02 21,2018 16:35:54
1,16.00,17.11,638.19,233.251,12.3,13.5
2,17.11,18.30,606.43,247.558,13.5,15.5
3,18.30,19.58,708.14,323.502,15.5,18.2
TimeStamp=Wednesday,02 21,2018 16:38:37
1,16.00,17.11,543.10,201.339,12.5,13.5
2,17.11,18.30,542.06,224.449,13.5,15.3
3,18.30,19.58,693.38,321.293,15.3,17.8