有tg机器人, 有机会以
webview(iframe)
打开网站,
在电报应用程序内部。当你按下机器人内部的按钮时,
它打开一个具有特定网址的网络视图。
这可以让我们了解打开的网站,
该网址已打开购买SOME_USER
并且他的身份验证数据是正确的(至少我这么认为)。
网址示例:
https://SOME_WEBSITE/#/login?
user=USER_GUID
&tgWebAppVersion=7.2
&linkBot=https://t.me/SOME_BOT_bot
&tgWebAppData=query_id=QUERY_ID
&user={
"id":1,
"first_name":"FirstName",
"last_name":"LastName",
"username":"UserName",
"language_code":"en",
"allows_write_to_pm":true
}
&auth_date=1713881657
&hash=SOME_HASH
&tgWebAppVersion=7.2
&tgWebAppPlatform=weba
&tgWebAppThemeParams={"bg_color":"#ffffff", ......... , "destructive_text_color":"#e53935"}
此网址不是由机器人生成的。该机器人仅包含
https://SOME_WEBSITE/#/login
这部分位于按钮内部。但当你按下一个按钮时
电报本身将所有这些特定的身份验证数据添加到 url 参数中。
并在网络视图中打开这个网址(我在按下按钮后拦截了这个网址)。
问题: “我如何自己生成这样的 URL 参数?”
我已经尝试过的:
Messages_RequestUrlAuth
, Messages_AcceptUrlAuth
)
来自“wtelegramclient”库。没有成功,可能做错了什么(收到空值)var resolvedUser = await _client.Contacts_ResolveUsername("someBotUserName");
var msgBase = await _client.Messages_GetHistory(new InputPeerUser(resolvedUser.User.ID, resolvedUser.User.access_hash), limit: 1);
var test1 = await _client.Messages_RequestUrlAuth(url: "https://some_url");
var test2 = await _client.Messages_AcceptUrlAuth(new InputPeerUser(resolvedUser.User.ID, resolvedUser.User.access_hash), msg_id: msgBase.Messages[0].ID, url: "https://some_url");
终于!找了好久
telegram api docs
+ gramJS lib
,找到了解决办法!
我们需要使用
Messages_RequestWebView
中的WTelegramClinet
方法,同样的方法也存在于gramJS
中。
//some basic theme params, perhaps it may be different per user, but it doesn't matter
var tgThemeParams = new
{
bg_color = "#ffffff",
text_color = "#000000",
hint_color = "#707579",
link_color = "#3390ec",
//......
};
var themeParams = JsonConvert.SerializeObject(tgThemeParams);
//resolvedUser is the chat(bot) where you need to sign in
var resolvedUser = await _client.Contacts_ResolveUsername(setting.ChatName!);
var userPeer = new InputPeerUser(resolvedUser.User.ID, resolvedUser.User.access_hash);
var webViewRes = await client.Messages_RequestWebView(
peer: userPeer,
bot: userPeer,
platform: "android",
reply_to: null,
url: "url from button / or url you need to sign in",
theme_params: new DataJSON { data = themeParams },
start_param: null,
send_as: null,
from_bot_menu: true,
silent: false
);
结果将是
url
,并且需要所有auth data
!