我有两张桌子,
Table Customer
ID | CustomerNumber | Name | City | PhoneNumber
Table Accounts
ID | CustomerNumber | AccountNumber | Bank
Customer表中的关系是CustomerNumber
我的客户映射
public class Customer {
@Id
@Column(name = "ID")
private Integer ID;
@Column(name = "CustomerNumber")
private Integer customerNumber;
@Column(name = "Name")
private String name;
@Column(name = "City")
private String city;
@Column(name = "PhoneNumber")
private Integer phoneNumber;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "customerNumber")
private Collection<Account> accounts;
}
和帐户映射
public class Account {
@Id
@Column(name = "ID")
private Integer ID;
@JoinColumn(name = "CustomerNumber", referencedColumnName="CustomerNumber")
@ManyToOne(fetch = FetchType.LAZY)
private Customer customer;
@Column(name = "AccountNumber")
private Integer accountNumber;
@Column(name = "Bank")
private String bank;
}
功能我DAO
public SearchResult listByCriteria(Customer object, int maxResults, String sortProperty, boolean ascending) {
SearcResult result = new SearchResult();
int resultSize = 0;
Criteria customerCriteria = ((Session)em.getDelegate()).createCriteria(Customer.class);
if(maxResults > 0) {
customerCriteria.setMaxResults(maxResults);
}
try {
if(object != null) {
customerCriteria = QueryHelper.getCustomerCriteria(object, customerCriteria, "");
resultSize = QueryHelperUtil.countResults(customerCriteria);
result.setSize(resultSize);
customerCriteria.setFirstResult(index);
QueryHelperUtil.sortResults(customerCriteria, sortProperty, ascending);
result.setList(customerCriteria.list());
}
} catch (Exception ex) {
error(ex);
}
return result;
}
QueryHelper.getCustomerCriteria
public static Criteria getCustomerCriteria(Customer object, Criteria criteria, String alias) {
if (object != null) {
if (object.getCustomerNumber() != null && object.getCustomerNumber() > 0) {
criteria.add(Restrictions.eq(alias+"customerNumber", object.getCustomerID()));
}
if (!StringUtil.isNullOrEmpty(object.getName())) {
criteria.add(Restrictions.like(alias+"name", QueryHelperUtil.createLikeStatement(object.getName())));
}
if (!StringUtil.isNullOrEmpty(object.getCity())) {
criteria.add(Restrictions.like(alias+"city", QueryHelperUtil.createLikeStatement(object.getCity())));
}
if (object.getPhoneNumber())) {
criteria.add(Restrictions.eq(alias+"phoneNumber", object.getPhoneNumber()));
}
}
}
现在我想只搜索有银行账户的客户。我想在Hibernate中设置一个标准。但我只是不知道该怎么做?
搜索时,您可以输入customerNumber,customer name,phonenumber和/或city,并选择要显示的结果数量。
首先我想我可以编写一个命名查询,但是你有搜索结果编号和在不同列上排序结果的功能。
我在这里搜索并查看了不同的类似问题,但我无法让它工作。我试图在一个函数中添加一个帐户标准,用于按标准列出客户,但它只是不起作用,我不知道它是否与该帐户是一个集合有关?
有人可以帮帮我吗?
我在我的方法listbycriteria中添加了以下内容
customerCritera.setFetchMode("accounts",FetchMode.JOIN);
Criteria accountCriteria = customerCriteria.createAlias("accounts","accounts");
在if(Object!= null)和resultSize = QueryHelperUtil.countResults(customerCriteria)之间;
我不知道您如何确定哪个帐户是银行帐户。但是,你可能想要这样的东西:
Criteria criteria = getCurrentSession().createCriteria(Customer.class,"cust");
criteria.createAlias("cust.accounts","acc");
criteria.list();
要检查帐户是否有银行编号,请添加:
.add(Restrictions.isNotNull("acc.bank"));
在.list()之前