Hibernate OneToOne关系java.lang.NullPointerException

问题描述 投票:0回答:1

我正在为我的Spring项目制作购物车,我有用户实体,购物车和书籍,一个用户只能有一个购物车,所以我在用户和购物车之间建立了OneToOne关系,也有很多购物车可以包含很多书,所以我创建了很多ToMany关系在购物车和书之间我的代码:

书籍实体:

         @ManyToMany
        @JoinTable(
        name = "books_in_cart",
        joinColumns = { @JoinColumn(name = "cart_id")},
        inverseJoinColumns = { @JoinColumn(name = "book_id")}
)
private Set<Cart> inCarts = new HashSet<>();

购物车实体:

@Entity
public class Cart {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int id;


@OneToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "idUsers")
private User user;

public User getUser() {
    return user;
}

public void setUser(User user) {
    this.user = user;
}

@ManyToMany
@JoinTable(
        name = "books_in_cart",
        joinColumns = { @JoinColumn(name = "book_id")},
        inverseJoinColumns = { @JoinColumn(name = "cart_id")}
)
private Set<Book> books = new HashSet<>();

public int getId() {
    return id;
}

public void setId(int id) {
    this.id = id;
}

public Set<Book> getBooks() {
    return books;
}

public void setBooks(Set<Book> books) {
    this.books = books;
}
}

和用户实体

@OneToOne(mappedBy = "user",cascade = CascadeType.MERGE,fetch = FetchType.EAGER,orphanRemoval =  true)
private Cart userCart = new Cart();

我用来将书添加到用户购物车的代码:

@PostMapping(value = "/addToCart")
@Secured("USER")
public String addToCart(@RequestParam(name = "ids") int id,Principal principal){
    System.out.println(principal.getName());
    User login = userDao.getByLogin(principal.getName());
    Book book = service.getById(id);
    login.getUserCart().setUser(login);
    login.getUserCart().getBooks().add(book);
    userDao.save(login);
    return "redirect:/books";
}

我得到了这个例外:

java.lang.NullPointerException controller.libraryController.addToCart(libraryController.java:170)sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)

java spring hibernate jpa
1个回答
1
投票

映射肯定是错误的,可能是整个模型,因为看起来你根本没有连接表:

joinColumns = { @JoinColumn(name = "cart_id")},
inverseJoinColumns = { @JoinColumn(name = "book_id")}

这意味着,一个实体在一个表中有一个名为cart_id的id,在另一个表中有一个book_id,这没有任何意义。这就是抛出异常的原因。

您需要修复模型,包括数据库和映射。 Here's很好地阅读了它。

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