具有多个参数的MapStruct QualifiedByName

Question

我遇到过一种情况，我的映射方法有3个参数，所有这三个参数都用于导出目标类型的一个属性。

我在界面中创建了一个默认的映射方法，保留了导出属性的逻辑，现在为了调用这个方法，我可以在expression = "java( /*method call here*/ )"注释中使用@Mapping。

是否有任何方法可以使用像@qualifiedByName这样的任何mapstruct注释，我尝试注释具有表达式属性的注释并使用qualifiedByName，但它不起作用：

@Mapper
public interface OneMapper {

    @Mapping(target="id", source="one.id")
    //@Mapping(target="qualified",expression = "java( checkQualified (one, projId, code) )")
    @Mapping(target="qualified",qualifiedByName="checkQualifiedNamed")
    OneDto createOne (One one, Integer projId, Integer val, String code);

    @Named("checkQualifiedNamed")
    default Boolean checkQualified (One one, Integer projId, Integer val, String code) {
        if(one.getProjectId() == projId && one.getVal() == val && one.getCode().equalsIgnoreCase(code)) {
            return Boolean.TRUE;
        }
        return Boolean.FALSE;                   
    }
}

Answer 1

目前，MapStruct不支持具有多个源属性的映射方法。

但是，在您的情况下，您可以使用1.2.0中的@Context。根据我的理解，projId和code就像映射的帮助器一样，它们不用于映射目标属性。

所以你可以做一些事情（它应该在理论上起作用）：

@Mapper
public interface OneMapper {

    @Mapping(target="id", source="one.id")
    @Mapping(target="qualified", qualifiedByName="checkQualifiedNamed")
    OneDto createOne (One one, @Context Integer projId, @Context String code);

    @Named("checkQualifiedNamed")
    default Boolean checkQualified (One one, @Context Integer projId, @Context String code) {
        if(one.getProjectId() == projId && one.getCode().equalsIgnoreCase(code)) {
            return Boolean.TRUE;
        }
        return Boolean.FALSE;                   
    }
}

另一种方法是将所有这些属性提取到一个单独的类中并传递它（这将允许多个相同类型的参数）。

该课程如下：

public class Filter {

    private final Integer projId;
    private final Integer val;
    private final String code;

    public Filter (Integer projId, Integer val, String code) {
        this.projId = projId;
        this.val = val;
        this.code = code;
    }

    //getters
}

您的映射器将如下所示：

@Mapper
public interface OneMapper {

    @Mapping(target="id", source="one.id")
    @Mapping(target="qualified", qualifiedByName="checkQualifiedNamed")
    OneDto createOne (One one, @Context Filter filter);

    @Named("checkQualifiedNamed")
    default Boolean checkQualified (One one, @Context Filter filter) {
        if(one.getProjectId() == filter.getProjId() && one.getVal() == filter.getVal() && one.getCode().equalsIgnoreCase(filter.getCode())) {
            return Boolean.TRUE;
        }
        return Boolean.FALSE;                   
    }
}

然后，您可以调用映射器：mapper.createOne(one, new Filter(projId, val, code));

Answer 2

从版本1.2开始支持：http://mapstruct.org/documentation/stable/reference/html/#mappings-with-several-source-parameters

例如这样：

@Mappings({
  @Mapping(source = "person.description", target = "description"),
  @Mapping(source = "address.houseNo", target = "houseNumber")
})
DeliveryAddressDto personAndAddressToDeliveryAddressDto(Person person, Address address);