[Spring Batch在读取XML时未填充对象

问题描述 投票:0回答:2

我正在尝试使用Spring Batch读取xml文件,因此我可以解析出某些数据并将其放置在dat文件中。但是,每当我尝试处理文件时,都会收到NullPointerException。调查原因,似乎我要填充值的对象被设置为null。它会创建一个在xml中找到的相同数量的School标记的列表,但是值是null。以下是我尝试读取的xml的示例以及用于填充对象的代码。我在做什么错?

ItemReader

@Bean
ItemReader<school> underwritingXmlFileItemReader(){     //Environment environment
    StaxEventItemReader<School> xmlFileReader = new StaxEventItemReader<>();

    xmlFileReader.setResource(editedInput);
    xmlFileReader.setFragmentRootElementName("school");
    Jaxb2Marshaller schoolMarshaller = new Jaxb2Marshaller();
    schoolMarshaller.setClassesToBeBound(School.class);
    xmlFileReader.setUnmarshaller(schoolMarshaller);    
    return xmlFileReader;
}

School.class

@XmlRootElement(name="School", namespace="http://schemas.datacontract.org/2004/07/Diamond.Business.ThirdParty.School.Adapters.Prelude")
@XmlAccessorType(XmlAccessType.NONE)
public class School {

    @XmlElement(name="SchoolNumber", defaultValue="")
    private String uniqueId;

    @XmlElement(name="Teacher", defaultValue= "")
    private Teacher teacher;

    public String getUniqueId() {
        return uniqueId;
    }
    public void setUniqueId(String uniqueId) {
        this.uniqueId = uniqueId;
    }
    public Policyholder getPolicyholder() {
        return policyholder;
    }
    public void setTeacher(Teacher teacher) {
        this.policyholder = policyHolder;
    }
}

Teacher.class

@XmlRootElement(name="Teacher", namespace="http://schemas.datacontract.org/2004/07/Diamond.Business.ThirdParty.School.Adapters.Prelude")
@XmlAccessorType(XmlAccessType.NONE)
public class Teacher {

    @XmlElement(name = "DisplayName", defaultValue="")
    private String fullName;

    @XmlElement(name = "DOB", defaultValue="")
    private String dob;

    public String getFullName() {
        return fullName;
    }
    public void setFullName(String fullName) {
        this.fullName = fullName;
    }
    public String getDob() {
        return dob;
    }
    public void setDob(String dob) {
        this.dob = dob;
    }
}

SchoolList.xml


    <SchoolList xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/Diamond.Business.ThirdParty.School.Adapters.Prelude">
  <School>
      <Teacher>
        <DOB>1/1/1970</DOB>
        <DisplayName>Ziva Brown</DisplayName>
        <DoingBusinessAs />
        <FirstName>Ziva</FirstName>
        <LastName>Brown</LastName>
        <MiddleName />
      </Teacher>
  </School>
  <School>
     <Teacher>
        <DOB>1/1/1970</DOB>
        <DisplayName>Alex John</DisplayName>
        <DoingBusinessAs />
        <FirstName>Alex</FirstName>
        <LastName>John</LastName>
        <MiddleName />
     </Teacher>
  </School>
</SchoolList>

xml spring-batch xmlreader
2个回答
0
投票

您的XML包装在SchoolList标记中

那么您的SchoolList.java在哪里?


0
投票

此处理器正在寻找“学校”根元素名称。您的xml中没有此类元素。更改此:

xmlFileReader.setFragmentRootElementName("school");

对此:

xmlFileReader.setFragmentRootElementName("School");
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