从1 - 7中选择并回显行

Question

您好我一直在尝试理解选择和回显表中有限的行数，但我不明白如何在代码中实现它所以我希望有人可以帮助

我有这个代码，我首先想要在循环中回显，只有列id为1-7（这也是第1-7行）我怎么能这样做我明白这应该是这样做的方法：

SELECT * FROM
(
SELECT ROW_NUMBER() OVER(ORDER BY ID) NUM,
* FROM bangpakong
) 
WHERE NUM >0 AND NUM <7

但是上面只是给我一个语法错误，当我在代码中使用它时，以下是代码工作，而不只是在1-7之间选择行

$sql = "SELECT * FROM bangpakong";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<div class='boks'>";
    echo "<div id='courseC'>";
echo "<img src='http://pattayasports.org/calendar/wp-
content/uploads/2017/11/Bangpakong-2.jpg' />";
echo "<p class='pleft'>Contact: 038 500 500 - 081 761 4874</p>";
echo "</div>";
echo "<div id='Crate'>";



    echo "<div class='Cheader'>";
        echo "<div>";

            echo "<div>Day</div>";
            echo "<div>PSC GF</div>";
            echo "<div>Visitor GF</div>";
            echo "<div>Cart</div>";
            echo "<div>Caddy</div>";


        echo "</div>";
    while($row = mysqli_fetch_array($result)){
        echo "<div>";

            echo "<div>" . $row['day'] . "</div>";
            echo "<div>" . $row['cf'] . "</div>";
            echo "<div>" . $row['viscf'] . "</div>";
            echo "<div>" . $row['cart'] . "</div>";
            echo "<div>" . $row['caddy'] . "</div>";
            echo "<div>" . $row['note'] . "</div>";
        echo "</div>";
    }
    echo "</div>";
    echo "</div>";
    echo "</div>";
    // Free result set
    mysqli_free_result($result);
} else{
    echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($link);

Answer 1

除非您使用的是支持ROW_NUMBER分析函数的非常新版本的MySQL，否则您的查询将无法在MySQL上运行。但是如果你想通过ID列排序表中的前7条记录，我们可以使用LIMIT来达到同样的效果：

SELECT *
FROM bangpakong
ORDER BY ID
LIMIT 7;