l = [“ a”,“ b”,“ b”][[x(l.count(x)] for set(l)中的x]]
d = {'P' : 1, 'B' : 3, 'K' : 3, 'R' : 5, 'Q' : 9} def chess_score(string): return sum(map(lambda x : d[x], string)) print(chess_score('BQBP')) # Output : 16