我在视图中存储了两个日期。而且我正在使用getItemValue来检索它们。
Dim repsondedDate As NotesDateTime
Set repsondedDate = timePart1doc.GetItemValue("dateResponded")
[当我尝试执行以下操作时,在运行时出现类型不匹配。
Dim dateDifference As double
Set dtLocal = New NotesDateTime( Now )
dateDifference = repsondedDate.Timedifference(dtLocal)
有人对出什么问题有任何想法吗?
以下行返回一个数组:
Set repsondedDate = timePart1doc.GetItemValue("dateResponded")
所以应该是:
Set repsondedDate = timePart1doc.GetItemValue("dateResponded")(0)
如果我没记错的话,您应该使用GetItemValueDateTimeArray方法而不是GetItemValue,因此实际上应该是这样的:
Set repsondedDate = timePart1doc.GetItemValueDateTimeArray("dateResponded")(0)
希望有所帮助
[使用GetItemValueDateTimeArray代替下面的IBM example:
Sub Initialize
Dim session As New NotesSession
Dim db As NotesDatabase
Dim dc As NotesDocumentCollection
Dim doc As NotesDocument
Dim count As Integer
Set db = session.CurrentDatabase
Set dc = db.UnprocessedDocuments
If dc.Count = 0 Then Exit Sub
Set doc = dc.GetFirstDocument
Dim times As Variant
times = doc.GetItemValueDateTimeArray("Times")
count = 0
Forall t In times
count = count + 1
If Typename(t) = "NOTESDATETIME" Then
Messagebox t.LocalTime,, "Date/time # " & count
Elseif Typename(t) = "NOTESDATERANGE" Then
Messagebox t.StartDateTime.LocalTime & " - " & _
t.EndDateTime.LocalTime,, "Date/time # " & count
End If
End Forall
End Sub