如何在Java中使用Dropwizard获取swagger.json

问题描述 投票:0回答:1

我正在使用Dropwizard创建我的服务和REST API,并在我的项目中添加了dropwizard-swagger,以便可以在UI上轻松访问此API。我正在创建一个CLI工具,它将使用openapi-generator在UI端生成我的API的Typescript模型:

openapi-generator generate -g typescript-fetch -i http://localhost:8080/swagger.json -o ~/Desktop/test

但是,我需要swagger.json定义,并且当前正在从路径http://localhost:8080/swagger.json的GET请求中获取这些定义。我想通过CLI Java项目以编程方式获取swagger.json(如何在不启动服务器的情况下获取swagger规范)。我正在寻找以编程方式生成swagger.json的方法,并尝试使用swagger-maven-plugin:

            <plugin>
            <groupId>com.github.kongchen</groupId>
            <artifactId>swagger-maven-plugin</artifactId>
            <version>3.1.4</version>
            <configuration>
                <apiSources>
                    <apiSource>
                        <springmvc>false</springmvc>
                        <locations>
                            <location>me.pablo.api.LauraPortraitsRestMethods</location>
                        </locations>
                        <schemes>http,https</schemes>
                        <host>http://localhost:8080/</host>
                        <basePath>/swagger</basePath>
                        <info>
                            <title>My project</title>
                            <version>v1</version>
                            <description>Do this late</description>
                            <termsOfService>
                                http://www.github.com/kongchen/swagger-maven-plugin
                            </termsOfService>
                            <contact>
                                <email>[email protected]</email>
                                <name>Kong Chen</name>
                                <url>http://kongch.com</url>
                            </contact>
                            <license>
                                <url>http://www.apache.org/licenses/LICENSE-2.0.html</url>
                                <name>Apache 2.0</name>
                            </license>
                        </info>
                        <templatePath>${basedir}/generated-sources/strapdown.html.hbs</templatePath>
                        <outputPath>${basedir}/generated-sources/document.html</outputPath>
                        <swaggerDirectory>${basedir}/generated-sources/</swaggerDirectory>
                    </apiSource>
                </apiSources>
            </configuration>
            <executions>
                <execution>
                    <phase>compile</phase>
                    <goals>
                        <goal>generate</goal>
                    </goals>
                </execution>
            </executions>
        </plugin>

以及Rest方法的类

package me.pabloestrada.api;

import com.google.inject.Inject;
import io.swagger.annotations.Api;
import io.swagger.annotations.ApiOperation;

import javax.ws.rs.GET;
import javax.ws.rs.Path;

@Path("/laura")
@Api(value = "/laura")
public class LauraPortraitsRestMethods
{
    private LauraPortraitsService delegate;
@Inject
public LauraPortraitsRestMethods(final LauraPortraitsService delegate) {
    this.delegate = delegate;
}

@GET
@ApiOperation(value = "Getting developer name")
@Path("/dev")
public String getDeveloperName() {
    return delegate.getDeveloperName();
}
}

[当我运行mvn clean compile时,看不到任何东西生成。我看不到swagger-maven-plugin的任何输出。有没有人有任何建议可以完成这项工作,或者有其他方法以编程方式获取swagger.json?]

java maven swagger dropwizard
1个回答
0
投票

如果有人还在寻找,请将其添加到您的Maven构建插件中:

<plugin>
    <groupId>com.github.kongchen</groupId>
    <artifactId>swagger-maven-plugin</artifactId>
                <version>3.1.8</version>
                <configuration>
                    <apiSources>
                        <apiSource>
                            <springmvc>false</springmvc>
                            <locations>
                                <location>me.pabloestrada.api.*</location>
                            </locations>
                            <schemes>http,https</schemes>
                            <outputFormats>json</outputFormats>
                            <basePath>/</basePath>
                            <host>127.0.0.1:8000</host>
                            <info>
                                <title>APIs</title>
                                <version>1.0.0</version>
                                <description>APIs</description>
                                <contact>
                                    <email>[email protected]</email>
                                    <name>Support</name>
                                </contact>
                                <license>
                                    <url>http://www.apache.org/licenses/LICENSE-2.0.html</url>
                                    <name>Apache 2.0</name>
                                </license>
                            </info>
                            <swaggerDirectory>swagger</swaggerDirectory>
                            <swaggerFileName>swaggerspec</swaggerFileName>
                        </apiSource>
                    </apiSources>
                </configuration>
                <executions>
                    <execution>
                        <phase>compile</phase>
                        <goals>
                            <goal>generate</goal>
                        </goals>
                    </execution>
                </executions>
            </plugin>

它将创建一个swagger目录,并在该目录中创建一个包含swaggerspec的json文件,名为swaggerspec.json。

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