如何从多行观察中获得整齐的数据？ [重复]

Question

我想制作一个 ggplot 箱线图，我想我需要从此格式化我的数据：

markerID        V1        V2        V3
       1 0.8636364 0.8409091 0.7954545
       2 0.8863636 0.8409091 0.8409091

对此：

markerID  replicate      rate
       1          1 0.8636364
       1          2 0.8409091
       1          3 0.7954545
       2          1 0.8863636
       2          2 0.8409091
       2          3 0.8409091

为了便于阅读，我只显示了部分数据。

我想一旦有了这种格式，我就可以按标记 ID 进行分组，然后制作箱线图。列数和行数可能会有所不同，因此我不确定如何应用诸如melt()或pivot_longer()之类的函数。

示例数据：

structure(list(markerID = c("1", "2", "3", "4", "5", "6", "7", 
"8", "9", "10", "11", "12", "13", "14", "15"), V1 = c(0.863636363636364, 
0.886363636363636, 0.886363636363636, 0.795454545454545, 0.795454545454545, 
0.863636363636364, 0.931818181818182, 0.909090909090909, 0.840909090909091, 
0.863636363636364, 0.886363636363636, 0.795454545454545, 0.818181818181818, 
0.863636363636364, 0.886363636363636), V2 = c(0.840909090909091, 
0.840909090909091, 0.909090909090909, 0.772727272727273, 0.772727272727273, 
0.909090909090909, 0.886363636363636, 0.886363636363636, 0.954545454545455, 
0.75, 0.818181818181818, 0.772727272727273, 0.681818181818182, 
0.863636363636364, 0.840909090909091), V3 = c(0.795454545454545, 
0.840909090909091, 0.886363636363636, 0.818181818181818, 0.818181818181818, 
0.795454545454545, 0.818181818181818, 0.863636363636364, 0.818181818181818, 
0.818181818181818, 0.931818181818182, 0.772727272727273, 0.772727272727273, 
0.886363636363636, 0.886363636363636)), class = "data.frame", row.names = c(NA, 
-15L))

Answer 1

使用

pivot_longer

的方法

library(tidyr)

pivot_longer(df, -markerID, names_prefix="V", names_to="replicate", values_to="rate")
# A tibble: 45 × 3
   markerID replicate  rate
   <chr>    <chr>     <dbl>
 1 1        1         0.864
 2 1        2         0.841
 3 1        3         0.795
 4 2        1         0.886
 5 2        2         0.841
 6 2        3         0.841
 7 3        1         0.886
 8 3        2         0.909
 9 3        3         0.886
10 4        1         0.795