如何在pymodbus输入寄存器中表示负数?

问题描述 投票:0回答:1

我想将负数分配给pymodbus异步服务器中的输入寄存器。我有一个名为PQV的5元素数组,其中包含幅度范围为0到300的数字,但有些元素是负数

PQV=[145, -210, 54, 187, -10]

我使用下面的代码将PQV分配给从地址0开始的输入寄存器(寄存器4)。我尝试将65536添加到所有负数,但这不起作用。

如何调整数组PQV的负面元素是否可以接受pymodbus?

context[slave_id].setValues(4, 0, PQV)
python modbus pymodbus
1个回答
0
投票

在写入数据存储区之前,浮点数将以IEEE-754十六进制格式表示。你可以做这样的事情来实现它。

# Import BinaryPayloadBuilder and Endian
from pymodbus.payload import BinaryPayloadBuilder, Endian
# Create the builder, Use the correct endians for word and byte
builder = BinaryPayloadBuilder(byteorder=Endian.Big, wordorder=Endian.Big)

在您的更新功能

busvoltages = [120.0, 501.3, -65.2, 140.3, -202.4]
builder.reset() # Reset Old entries
for vol in busvoltages:
    builder.add_32bit_float(vol)
payload = builder.to_registers()   # Convert to int values
# payload will have these values [17136, 0, 17402, 42598, 49794, 26214, 17164, 19661, 49994, 26214]
context[slave_id].setValues(2, 0, payload)  # write to datablock

当您读回值时,您将获得原始int值。你将不得不使用BinaryPayloadDecoder将它们转换回浮点数

>>> from pymodbus.payload import BinaryPayloadDecoder, Endian
>>> r = client.read_input_registers(0, 10, unit=1)
# Use the same byte and wordorders
>>> d = BinaryPayloadDecoder.fromRegisters(r.registers, byteorder=Endian.Big, wordorder=Endian.Big)
>>> d.decode_32bit_float()
120.0
>>> d.decode_32bit_float()
501.29998779296875
>>> d.decode_32bit_float()
-65.19999694824219
>>> d.decode_32bit_float()
140.3000030517578
>>> d.decode_32bit_float()
-202.39999389648438
>>> # Further reads after the registers are exhausted will throw struct error
>>> d.decode_32bit_float()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/Users/sanjay/.virtualenvs/be3/lib/python3.6/site-packages/pymodbus/payload.py", line 440, in decode_32bit_float
    handle = self._unpack_words(fstring, handle)
  File "/Users/sanjay/.virtualenvs/be3/lib/python3.6/site-packages/pymodbus/payload.py", line 336, in _unpack_words
    handle = unpack(up, handle)
struct.error: unpack requires a buffer of 4 bytes
>>>

希望这可以帮助。

© www.soinside.com 2019 - 2024. All rights reserved.