用户输入了1个以上的项目并计算总价格

Question

如果允许用户在购物车中添加其他商品，我该怎么做才能计算出用户购买的商品的总价？ chosen1的值是否会更改，还是仅添加新项而不删除chosen1中存储的先前值？我必须在这里使用数组吗？我刚刚开始学习此方法，一切令人困惑； <

#include <stdio.h>
#include <stdlib.h>

 char chosen1;
 int  Qty1;
 printf("Pick your items:\n");
 printf("a-Onions\nb-Leek\nc-Pak Choy\nd-Bell Peppers\ne-Celery\nf-Chicken breast\ng-Chicken thigh\nh-Salmon\ni-Meat\nj-Garlic\n");
 do
 {
 printf("Item?\n");
 scanf(" %c",&chosen1);
 }
 while ((chosen1 != 'a')&&(chosen1!='b')&&(chosen1!='c')&&(chosen1!='d')&&(chosen1!='e')&& 
 (chosen1!='f')&&(chosen1!='g')&&(chosen1!='h')&&(chosen1!='i')&&(chosen1!='j'));
 printf("Quantity?\n");
 scanf("%d",&Qty1);
 printf("Item:%c||Qty:%d\n",chosen1,Qty1);
 printf("Add another item?");

Answer 1

char和int之类的变量在每个时刻只能存储一个值。您不需要此任务的数组。为了计算总价，您可以定义float类型的变量（用于带点的数字），并使用运算符switch为每个项目添加适当的金额：

float totalPrice = 0;
...
float costOfItem;
switch (chosen1)  // we going to appropriate "case" depending on value of chosen1
{
  case 'a': costOfItem = 10.5; break; // here must be cost of onions
  case 'b': costOfItem = 4.0; break;  // here must be cost of leek, etc
  ...
}
totalPrice += costOfItem * Qty1; // here we take the sum of left and right parts of operator "+=" and put it in the left part, i.e. in variable totalPrice