上传图像文件并将其绘制到画布中

问题描述 投票:0回答:3

我在一个用于绘制图像的网络应用程序中工作。我使用 CANVAS 元素和 JavaScript 在其上绘图,但有一个问题:如何从用户的 PC 加载图像并将其绘制在画布上?我不想保存在服务器上,只想保存在网页上。

这是代码的简化版本:

HTML:

Open file: <input type="file" id="fileUpload" accept="image/*" /><br />
<canvas id="canvas" onmousemove="keepLine()" onmouseup="drawLine()" onmousedown="startLine()" width="900" height="600" style="background-color:#ffffff;cursor:default;">
  Please open this website on a browser with javascript and html5 support.
</canvas>

JavaScript:

var x = 0;
var y = 0;
var clicked = false;

var canvas = document.getElementById("canvas");
var context = canvas.getContext("2d");

context.strokeStyle = "black";
context.lineCap = "round";

canvas.addEventListener('mousemove', function(e) { getMousePos(canvas, e); }, false);

takePicture.onchange = function (event) {
  var files = event.target.files,
    file;
  if (files && files.length > 0) {
    file = files[0];
    processImage(file);
  }
};

function processImage(file) {
  var reader = new FileReader();
  reader.readAsDataURL(file)
  reader.onload = function(e) {
    var img = new Image();
    img.onload = function() {
      context.drawImage(img, 100,100)
    }
    img.src = e.target.result;
  }
}

   // functions for drawing (works perfectly well)
function getMousePos(canvas, e) {
  var rect = canvas.getBoundingClientRect();
  x = evt.clientX - rect.left;
  y = evt.clientY - rect.top;
}

function startLine() {
  context.moveTo(x,y);
  context.beginPath();
  clicked = true;
}

function keepLine() {
  if(clicked) {
    context.lineTo(x,y);
    context.stroke();
    context.moveTo(x,y);
  }
}

function drawLine() {
  context.lineTo(x,y);
  context.stroke();
  clicked = false;
}

没有版权

javascript html canvas file-upload
3个回答
34
投票

const EL = (sel) => document.querySelector(sel);
const ctx = EL("#canvas").getContext("2d");

function readImage() {
  if (!this.files || !this.files[0]) return;
  
  const FR = new FileReader();
  FR.addEventListener("load", (evt) => {
    const img = new Image();
    img.addEventListener("load", () => {
      ctx.clearRect(0, 0, ctx.canvas.width, ctx.canvas.height);
      ctx.drawImage(img, 0, 0);
    });
    img.src = evt.target.result;
  });
  FR.readAsDataURL(this.files[0]);
}

EL("#fileUpload").addEventListener("change", readImage);
canvas {display: block;}
<input type='file' id="fileUpload" />
<canvas id="canvas" width="300" height="200"></canvas>


5
投票
<html>
<head>
<script type="text/javascript" src="http://fiddle.jshell.net/js/lib/mootools-core-1.4.5-nocompat.js"></script>
<script type="text/javascript">
//<![CDATA[ 
window.addEvent('load', function() {
var imageLoader = document.getElementById('imageLoader');
    imageLoader.addEventListener('change', handleImage, false);
var c = document.getElementById('myCanvas');
var ctx = c.getContext('2d');


function handleImage(e){
    var reader = new FileReader();
    reader.onload = function(event){
        var img = new Image();
        img.onload = function(){
            c.width = img.width;
            c.height = img.height;
            ctx.drawImage(img,0,0);
        }
        img.src = event.target.result;
    }
    reader.readAsDataURL(e.target.files[0]);     
}

});//]]>  


</script>
</head>

<body>
<div style="background:#990; width:100%; padding:20px; ">
<label>Image File:</label><br/>
<input type="file" id="imageLoader" name="imageLoader"/>
</div>

<canvas id="myCanvas" ></canvas>
</body>
</html>

2
投票

这是一个更简单的方法,它不使用低效的数据网址:

var canvas = document.getElementById('canvas')
var input = document.getElementById('input')
var c2d = canvas.getContext('2d')

input.onchange=function() {
    var img = new Image()
    img.onload = function() {
        canvas.width = this.width
        canvas.height = this.height
        c2d.drawImage(this, 0, 0)
        URL.revokeObjectURL(this.src)
    }
    img.src = URL.createObjectURL(this.files[0])
}
<input type=file id=input> <br>
<canvas id=canvas></canvas>

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