使用os rename在python中基于变量重命名文件

Question

我正在试图弄清楚如何将下载的文件从NWZV1WB重命名为HENRY。我敢打赌，现在它下载它作为NWZV1WB wget看到它。

重要提示：文件最后总是有数字NWZV1WB-1.jpg NWZV1WB-2.jpg NWZV1WB-3.jpg

我的代码看起来像这样：（Henry yuan - 帮帮我）

import wget
import os
import multiprocessing


def run_process(url, output_path):
    wget.download(url, out=output_path)


if __name__ == '__main__':
    cpus = multiprocessing.cpu_count()
    max_pool_size = 4
    pool = multiprocessing.Pool(cpus if cpus < max_pool_size else max_pool_size)
    base_dir = os.path.dirname(os.path.abspath(__file__))
    prefix_list = ["NWZV1WB"]
    folder_name_list = ["HENRY"]  
    download_list = []
    name_list = list(range(1, 7))
    for index, prefix in enumerate(prefix_list):  # return index and item
        folder_name = folder_name_list[index]  # changed
        path = os.path.join(base_dir)
        if not os.path.exists(path):
            os.mkdir(path)
        if not os.path.isdir(path):
            exit()
        for name in name_list:
            download_list.append(['https://example.com/{p}-{n}.jpg'.format(n=name, p=prefix), path])

    for url, path in download_list: 
        pool.apply_async(run_process, args=(url, path, ))
    pool.close()
    pool.join()

Answer 1

你的问题有点令人困惑，但是在评论主题中我认为我拼凑了你想要做的事情。目前您的输出是：

Old name:      New name:
NWZV1WB-1.jpg  NWZV1WB-1.jpg

Desired output is:
NWZV1WB-1.jpg  HENRY-1.jpg

您的新文件名在下载列表中的path变量中。试试这个：

for name in name_list:
    path = 'your path'
    newfile = path + folder_name +'-{n}.jpg'.format(n=name)
    download_list.append(['https://example.com/{p}-{n}.jpg'.format(n=name, p=prefix), newfile])

Answer 2

罪魁祸首就在这一行：

path = os.path.join(base_dir)

正如你在source code中看到的，只有一个参数join方法只返回它（这可能不是你想要的）。

def join(a, *p):
    """Join two or more pathname components, inserting '/' as needed.
    If any component is an absolute path, all previous path components
    will be discarded."""
    path = a
    for b in p:
        ...
    return path

Cody已经为您提供了答案，我将使用Python 3.6+ f-strings让它更清洁。

for name in name_list:
    file_path = os.path.join(base_dir, f'{folder_name}-{name}.jpg')
    download_list.append([f'https://example.com/{prefix}-{name}.jpg', file_path])