提供的c代码定期运行，我检查了调试器，它表明问题出在行：
UUo[irx][i] += dt * dt * slice[i][it];awe_2d_heterogeneous_8th_order_data_time_reverse这是代码：
#include <stdlib.h>
#include <math.h>
#include <time.h>
void awe_2d_heterogeneous_8th_order_data_time_reverse(
double** UUo, double** UUm, int nx, int ny, double dx, double dy,
double dt, double** v, double** slice, int it, double rx
) {
// Get dimensions of the wavefield
int irx = (int)(rx / dx); // Force to be integer
// Inject wavelet
for (int i = 0; i < nx; i++) {
// printf("i: %d\n", i);
UUo[irx][i] += dt * dt * slice[i][it]; //Debugger points to this line
}
// Define Courant numbers (squared)
double dtdx2 = (dt / dx) * (dt / dx);
double dtdy2 = (dt / dy) * (dt / dy);
// Update solution
for (int i = 4; i < nx - 4; i++) {
for (int j = 4; j < ny - 4; j++) {
UUm[i][j] = 2 * UUo[i][j] - UUm[i][j] + dtdx2 * v[i][j] * v[i][j] * (
-1.0/560 * UUo[i - 4][j]
+ 8.0/315 * UUo[i - 3][j]
- 1.0/5 * UUo[i - 2][j]
+ 8.0/5 * UUo[i - 1][j]
- 205.0/72 * UUo[i][j]
+ 8.0/5 * UUo[i + 1][j]
- 1.0/5 * UUo[i + 2][j]
+ 8.0/315 * UUo[i + 3][j]
- 1.0/560 * UUo[i + 4][j]) + dtdy2 * v[i][j] * v[i][j] * (
-1.0/560 * UUo[i][j - 4]
+ 8.0/315 * UUo[i][j - 3]
- 1.0/5 * UUo[i][j - 2]
+ 8.0/5 * UUo[i][j - 1]
- 205.0/72 * UUo[i][j]
+ 8.0/5 * UUo[i][j + 1]
- 1.0/5 * UUo[i][j + 2]
+ 8.0/315 * UUo[i][j + 3]
- 1.0/560 * UUo[i][j + 4]);
}
}
}
void append_2d_slice(double*** dest, double** src, int nx, int ny, int nt) {
for (int i = 0; i < nx; i++) {
for (int j = 0; j < ny; j++) {
dest[i][j][nt] = src[i][j];
}
}
}
void write_text_file_slice(double** slice, int nx, int ny, const char* filename) {
FILE *file = fopen(filename, "w");
if (file == NULL) {
fprintf(stderr, "Error opening file for writing.\n");
exit(1);
}
// Write slice data to the text file
for (int i = 0; i < nx; i++) {
for (int j = 0; j < ny; j++) {
fprintf(file, "%.50lf ", slice[i][j]);
}
fprintf(file, "\n");
}
fclose(file);
}
int main() {
// Define constants and arrays
int nz = 300;
int nx = 298;
double dz = 5.0;
double dx = 5.0;
double t0 = 0.05;
double CC = 0.5;
int nt = 2000;
double sx = 25;
double sy = 800;
// Initialize UUo and UUm with zeros
double** UUo = (double**)malloc(nz * sizeof(double*));
double** UUm = (double**)malloc(nz * sizeof(double*));
double** v = (double**)malloc(nz * sizeof(double*));
double** slice = (double**)malloc(nx * sizeof(double*));
for (int i = 0; i < nz; i++) {
UUo[i] = (double*)malloc(nx * sizeof(double));
UUm[i] = (double*)malloc(nx * sizeof(double));
v[i] = (double*)malloc(nx * sizeof(double));
}
for (int i = 0; i < nx; i++) {
slice[i] = (double*)malloc(nt * sizeof(double));
}
// Initialize mmm with zeros
double*** mmm = (double***)malloc(nz * sizeof(double**));
for (int i = 0; i < nz; i++) {
mmm[i] = (double**)malloc(nx * sizeof(double*));
for (int j = 0; j < nx; j++) {
mmm[i][j] = (double*)malloc(nt * sizeof(double));
}
}
// Time stepping parameters
double dt = CC * dz / 5560.328125; // Assuming 'v' is the maximum value
double t[nt];
for (int i = 0; i < nt; i++) {
t[i] = i * dt;
}
FILE *fileS = fopen("slice.txt", "r");
if (fileS == NULL) {
fprintf(stderr, "Error opening file.\n");
perror("fopen");
return 1; // Exit with an error code
}
for (int i = 0; i < nx; i++) {
for (int j = 0; j < nt; j++) {
if (fscanf(fileS, "%lf", &slice[i][j]) != 1) {
fprintf(stderr, "Error reading from file.\n");
fclose(fileS);
return 1; // Exit with an error code
}
}
}
fclose(fileS);
// Read 'v' from the file
FILE *file = fopen("marmousi.txt", "r");
if (file == NULL) {
fprintf(stderr, "Error opening file.\n");
perror("fopen");
return 1; // Exit with an error code
}
for (int i = 0; i < nz; i++) {
for (int j = 0; j < nx; j++) {
if (fscanf(file, "%lf", &v[i][j]) != 1) {
fprintf(stderr, "Error reading from file.\n");
fclose(file);
return 1; // Exit with an error code
}
}
}
fclose(file);
double rx = 25;
for (int it = nt - 1; it > 1900; it--) {
//printf("%d\n",it);
awe_2d_heterogeneous_8th_order_data_time_reverse(UUo, UUm, nz, nx, dz, dx, dt, v, slice, it, rx);
double** tmp = UUo;
UUo = UUm;
UUm = tmp;
append_2d_slice(mmm, UUo, nz, nx, nt - 1 - it);
}
double** slicep = mmm[5];
write_text_file_slice(slicep, nx, nt, "slicep.txt");
// Free allocated memory
for (int i = 0; i < nz; i++) {
free(UUo[i]);
free(UUm[i]);
free(v[i]);
}
free(UUo);
free(UUm);
free(v);
for (int i = 0; i < nx; i++) {
free(slice[i]);
}
free(slice);
for (int i = 0; i < nz; i++) {
for (int j = 0; j < nx; j++) {
free(mmm[i][j]);
}
free(mmm[i]);
}
free(mmm);
return 0;
}
以下是脚本中使用的txt文件的链接：https://drive.google.com/drive/folders/1pmSkKrxS7IWDGyPiyl0SuNEh3gidmyFS?usp=drive_link
我认为问题不在于索引，因为该程序偶尔会工作。我可能会错过一些与内存分配相关的内容。
你的代码 100% 在线时都会出现段错误：
UUo[irx][i] += dt * dt * slice[i][it];
看来您在调用中将
nznxawe_2d_heterogeneous_8th_order_data_time_reverse() awe_2d_heterogeneous_8th_order_data_time_reverse(UUo, UUm, nx, nz, dz, dx, dt, v, slice, it, rx);
一旦修复，你的程序就会终止，但每个 valgrind 都会显示“检测到的总错误数超过 10000000 个”。