如何使用HQL查找OneToMany映射中列的最大值?

问题描述 投票:0回答:1

这些是类 CountryState:

国家:

 @Entity
    @Table(name="Country")
    public class Country{
        @Id
        private String countryName;
        private String currency;
        private String capital;
        @OneToMany(mappedBy="country", cascade=CascadeType.ALL, fetch = FetchType.LAZY)
        private List<State> statelist = new ArrayList<State>();

州。

@Entity
 @Table(name="State")
 public class State{
     @Id
     private String stateName;
     private String language;
     private long population;
     @ManyToOne
     @JoinColumn(name="countryName")
     private Country country;

应该用什么HQL查询来检索某个国家人口最多的州(也许在一个列表中)?

这是我写的代码,我试图先检索人口最多的值,然后运行该国所有的州,以匹配每个人口值,并将州添加到一个列表中。但是,在这样做的时候,我得到的错误是,查询中的列定义模糊。

public List<State> stateWithMaxPopulation(String countryName){
    List<State> l = new ArrayList<State>();
    Country ctr = (Country)session.get(Country.class,countryName);
    String hql = "select max(stlst.population) from Country cntry "
    +" join cntry.statelist stlst where countryName=:cNm";

    Query query = session.createQuery(hql);
    query.setParameter("cNm", countryName);
    Long maxPop = (Long)query.uniqueResult();

    for(State st : ctr.getStatelist()){
        if(st.getPopulation() == maxPop)
            l.add(st);
    }

    return l;
}

正确的做法应该是什么呢?

java hibernate hql one-to-many hibernate-onetomany
1个回答
1
投票

你缺少实体的别名

select max(stlst.population) from Country cntry " +" join cntry.statelist stlst where cntry.countryName=:cNm1

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