添加具有相同接口的 HttpClient 最终具有相同的基本 url Asp.Net Core

Question

我有一个 ASP.Net Core 程序。我在

HttpClient

上添加了两个具有相同接口的

Startup.cs

类：

public class TypedClientA : ITypedClient
{
    private readonly HttpClient _httpClient;

    public class TypedClientA(HttpClient httpClient)
    {
        _httpClient = httpClient;
    }
}

public class TypedClientB : ITypedClient
{
    private readonly HttpClient _httpClient;

    public class TypedClientB(HttpClient httpClient)
    {
        _httpClient = httpClient;
    }
}

// Startup.cs
public void ConfigureServices(IServiceCollection services)
{
    ...
    services.AddHttpClient<ITypedClient, TypedClientA>(httpClient =>
    {
        httpClient.BaseAddress = new Uri("uri class A");
    });

    services.AddHttpClient<ITypedClient, TypedClientB>(httpClient =>
    {
        httpClient.BaseAddress = new Uri("uri class B");
    });
    ...
}

然后我尝试在控制器中调用它们，但是每个键入的客户端中的

HttpClient

实例始终具有相同的

BaseAddress

，即使我在启动期间为每个实例填充了不同的基本 URL。

public class SomeController : Controller
{
    private readonly IEnumerable<ITypedClient> _typedClients;

    public OtherService(IEnumerable<ITypedClient> typedClients)
    {
        _typedClients = typedClients;
    }
}

但是，如果我在

AddHttpClient

上没有界面的话

Startup.cs

:

public void ConfigureServices(IServiceCollection services)
{
    ...
    services.AddHttpClient<TypedClientA>(httpClient =>
    {
        httpClient.BaseAddress = new Uri("uri class A");
    });

    services.AddHttpClient<TypedClientB>(httpClient =>
    {
        httpClient.BaseAddress = new Uri("uri class B");
    });
    ...
}

public class SomeController : Controller
{
   private readonly TypedClientA _typedClientA;
   private readonly TypedClientB _typedClientB;

   public Class(TypedClientA typedClientA, TypedClientB typedClientB)
   {
      _typedClientA = typedClientA;
      _typedClientB = typedClientB;
   }
}

每个打字客户端上的

HttpClient

都会有自己的

BaseAddress

。

我做错了什么？我希望每个类型的客户端都具有相同的界面，但我也希望其中的每个

HttpClient

实例具有不同的

BaseAddress

。有什么解决办法吗？

Answer 1

.NET 依赖注入容器的工作方式是，当您为同一接口注册多个依赖项时，所有依赖项都将被注册，并且可以通过

IEnumerable<IInterface>

解决。因此，您的第一种方法不适用于您的情况。你的第二种方法很好。我认为没有任何理由在您的界面中显式注册它们。