在yesod测试中运行db动作

问题描述 投票:0回答:2

在我的yesod测试中,我希望能够在测试过程中修改db中的记录。

这是我想出的代码

        yit "post is created by authorized user" $ do
            request $ do
                addPostParam "ident" "dummy"
                setMethod "POST"
                setUrl ("http://localhost:3000/auth/page/dummy" :: Text)
            update 0 [UserAuthorized =. True]
            postBody PostR (encode $ object [
                "body" .= ("test post" :: Text),
                "title" .= ("test post" :: Text),
                "coverImage" .= ("test post" :: Text),
                "author" .= (0 :: Int)
                ])
            statusIs 200

这失败了,错误

• Couldn't match expected type ‘IO a0’
              with actual type ‘ReaderT backend0 m0 ()’
• In the second argument of ‘($)’, namely
    ‘update 0 [UserAuthorized =. True]’

  In a stmt of a 'do' block:
    runIO $ update 0 [UserAuthorized =. True]
  In the expression:
    do { settings <- runIO
                     $ loadYamlSettings
                         ["config/test-settings.yml", "config/settings.yml"] [] useEnv;
         foundation <- runIO $ makeFoundation settings;
         yesodSpec foundation $ do { ydescribe "Auth" $ do { ... } };
         runIO $ update 0 [UserAuthorized =. True];
         .... }

我可以说这是因为update返回m ()而不是像YesodExample site ()requestpostBody那样的statusIs

我怎样才能在此测试中进行数据库更新?

haskell testing integration-testing yesod yesod-test
2个回答
2
投票

你需要使用runDB函数。即:

runDB $ update 0  [UserAuthorized =. True]

0
投票

这有两个问题,第一个是Sibi指出的是我需要runDB第二个是你不能只用一个整数查找记录。

为了实现这一点,我使用了以下代码

runDB $ do
    (first :: Maybe (Entity User)) <- selectFirst [] []
    case first of
        Nothing -> pure () -- handle the case when the table is empty
        Just (Entity k _) -> update k [UserAuthorized =. True]

这个发现是数据库中的记录,然后更新它。修改(first :: Maybe (Entity User)) <- selectFirst [] []以选择要更新的记录。

© www.soinside.com 2019 - 2024. All rights reserved.