详细内容
我正在尝试用并发模式和继电器进行反应实验。我从来没有使用过中继,并且有一个有点困难的时间让一切工作,但是,我几乎没有。当使用react-relay钩子 useLazyLoadQuery
在没有任何碎片的情况下,一切都很好,我得到了我想要的结果。但是,当添加碎片时,我遇到了一些问题。
问题
当我设置了react-relay钩子的时候 useLazyLoadQuery
在父组件中包含子组件的片段,我得到以下错误信息。
属性'" $fragmentRefs"' 在类型'readonly { readonly " $fragmentRefs": FragmentRefs< "HomeView_getAllUsers">; }[]",但在 "HomeView_getAllUsers$key "类型中需要。
据我所知,我已经按照中继文档做了所有的事情,但有点卡在了为什么会出现这个错误。
疑问
为什么它找不到 $fragmentRefs
根据继电器生成的类型其有的属性。谁有办法解决这个问题?
编码
主页.tsx
import React from "react";
import { useLazyLoadQuery } from "react-relay/hooks";
import graphql from "babel-plugin-relay/macro";
import { HomeGetAllUsersQuery } from "./__generated__/HomeGetAllUsersQuery.graphql";
import HomeView from "./HomeView";
const Home: React.FC = (): React.ReactElement => {
const data = useLazyLoadQuery<HomeGetAllUsersQuery>(
graphql`
query HomeGetAllUsersQuery {
getAllUsers {
...HomeView_getAllUsers
}
}
`,
{},
{ fetchPolicy: "store-or-network" }
);
return <HomeView getAllUsers={data.getAllUsers} />;
};
export default Home;
主页查看.tsx
import React from "react";
import graphql from "babel-plugin-relay/macro";
import { useFragment } from "react-relay/hooks";
import { HomeView_getAllUsers$key } from "./__generated__/HomeView_getAllUsers.graphql";
type Props = {
getAllUsers: HomeView_getAllUsers$key;
};
const HomeView: React.FC<Props> = (props: React.PropsWithChildren<Props>): React.ReactElement => {
const data = useFragment<HomeView_getAllUsers$key>(
graphql`
fragment HomeView_getAllUsers on UserType {
username
}
`,
props.getAllUsers
);
return <div>{data.username}</div>;
};
export default HomeView;
图形QL
@ObjectType({ description: "Object representing a user" })
class UserType {
@Field(() => ID)
id!: number;
@Field()
username!: string;
}
@Query(() => [UserType], { description: "Returns all users" })
async getAllUsers(): Promise<User[]> {
const users = await User.findAll({});
if (!users) {
throw new Error("No users could be found");
}
return users;
}
继电器生成类型
export type HomeView_getAllUsers$key = {
readonly " $data"?: HomeView_getAllUsers$data;
readonly " $fragmentRefs": FragmentRefs<"HomeView_getAllUsers">;
};
我想明白了。GraphQL查询返回一个包含所有用户的数组,而我在子组件中要求一个用户,所以我只需要将结果映射过来,并将其传递给子组件。
const renderUsers = (): React.ReactNode => {
return data.getAllUsers.map((user, index) => (
<HomeView key={data.getAllUsers[index].id} getAllUsers={user} />)
);
}
return <div>{renderUsers()}</div>;