Laravel：如何在刀片视图中拆分/获取json嵌套元素？

Question

[当我通过下面的视图时，刀片显示了从mongo获取的整个Json结构。

{!! $fees !!}

输出：

[{"_id":"5e04a06ca445f78401a16d0a","University":[{"fees":"$200"},{"month":"June"}]}]

现在如何获取嵌套的内容。我想在刀片中显示Fees = $ 200和Month = June）>

经过这样的尝试，但结果是刀片上的'空白'而没有任何错误。嵌套的open / closes：[是否存在任何问题，它在上述JSOn输入中的'University：'之后。请建议

@foreach ($fees as $value)   
    {{$content[] = $value->['University'] }}  
    @foreach ($content as $key)
        <h1>{{ $key['fees'] }}</h1>
        <h1>{{ $key['month'] }}</h1>
    @endforeach
@endforeach
我之前的步骤在这里给出：Laravel not fetching result from mongodb

编辑（1）：

我尝试过这样，所以刀片视图上的结构。

<?php
$get_result = json_decode($fees, true);

#$get_result = implode(",", array_flatten($get_result));
#print_r($get_result);
#$get_result2 = json_encode($get_result, true);

echo "</br>";
print_r($get_result)
?>
输出：

Array ([0] => Array ([_id] => 5e04a06ca445f78401a16d0a [University] 
=> Array ([0] => Array ( [fees] => $200 ) [1] => Array ( [month] => June ) )))
也，

<?php
echo htmlentities (print_r (json_encode ($fees), true));
?>
输出：

"[{\"_id\":\"5e04a06ca445f78401a16d0a\",
   \"University\":[{\"fees\":\"$200\"},{\"month\":\"June\"}]}]"
也是从Controller我也尝试如下：

..
public function getFees()
{

  # database fetch test (with any one of the db query)
  $fees = Finance::all();

  $fees = Finance::where(['University.month' => 'June'])->get()->toArray();

  $fees = Finance::where('University.month', 'June')->first();

  $fees = Finance::where('University.month', 'June')->get();


  # Return test (with any one of the return)
  return view('tables')->with('fees', json_encode($fees, true));

  return view('tables', compact('fees'));

  return view('tables')->with(compact('fees'));

  return view('tables')->with('fees', $fees);

 }
  ..
编辑（2）：

在刀片中，我尝试了如下操作，但由于出现异常：试图获取非对象的属性“费用”>

<?php
$fees = json_decode($fees, true); 
#echo "</br>";
#print_r($fees)
?>

    @foreach ($fees[0] as $value)   
    @php $content = $value->University @endphp  // or without @
    @foreach ($content as $key)
        <h1>{{ $key['fees'] }}</h1>
        <h1>{{ $key['month'] }}</h1>
    @endforeach
@endforeach
根据Chandan的建议编辑（3）。
<?php

$fees = json_decode($fees); 
$univ = $fees[0]->University; 
//print_r($univ); 

foreach ($univ as $key => $value) 
{ 
foreach($univ[$key] AS $k =>$v)
{ 
echo $k." " .$v; 
} 
}
?>
输出：
 fees $200month June
仅输出是合并而没有逗号分隔的内容。我可以如下显示它们吗？>
费用= $ 200月=六月
或作为html

<td>{{$k}}</td><td>{{$v}}</td>
[当我通过下面的视图时，刀片显示了从mongo获取的整个Json结构。 {!! $ fees !!}输出：[{“ _id”：“ 5e04a06ca445f78401a16d0a”，“大学”：[{“ fees”：“ $ 200”}，{“ month”：“ June” ...

< [

它的工作方式如下：-

@foreach ($fees as $value)   
    {{$content[] = $value->['University'] }} 

    @if($content->['fees']!==null)
        <h1>{{ $content['fees'] }}</h1>
    @else
        <h1>-</h1>
    @endif

    @if($content->['fees']!==null)
        <h1>{{ $content['fees'] }}</h1>
    @else
        <h1>-</h1>
    @endif

@endforeach

您可以尝试以下方法：
@foreach ($fees as $value)   
    @php $content = $value->['University'] @endphp
    @foreach ($content as $key)
        <h1>{{ $key['fees'] }}</h1>
        <h1>{{ $key['month'] }}</h1>
    @endforeach
@endforeach

Answer 1

它的工作方式如下：-

Answer 2

您可以尝试以下方法：

@foreach ($fees as $value)   
    @php $content = $value->['University'] @endphp
    @foreach ($content as $key)
        <h1>{{ $key['fees'] }}</h1>
        <h1>{{ $key['month'] }}</h1>
    @endforeach
@endforeach