ES6：mailchimp api的对象重构

Question

我想构建一个基于数组和另一个对象的对象。

目标是发送给mailchimp api我的用户兴趣，为此，我有：

//Array of skills for one user    
const skillsUser1 = ["SKILL1", "SKILL3"]

//List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
  'SKILL1': 'list_id_1',
  'SKILL2': 'list_id_2',
  'SKILL3': 'list_id_3',
}

//Mapping of user skill to all skills
const outputSkills = skillsUser1.map((skill) => skillsMailchimpId[skill]);
console.log(outputSkills);

问题出在后面，outputSkill给我一个数组：

["ID1", "ID3"]

但是什么mailchimp api need，所以我需要的是：

{ "list_id_1": true,
  "list_id_2": false, //or empty
  "list_id_3" : true
}

Answer 1

一个简单的方法是这样（请参阅代码中的注释以获得解释）：

// Array of skills for one user    
const skillsUser1 = ["SKILL1", "SKILL3"]

// List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
  'SKILL1': 'list_id_1',
  'SKILL2': 'list_id_2',
  'SKILL3': 'list_id_3',
}

// Create an output object
const outputSkills = {};

// Use `Object.entries` to transform `skillsMailchimpId` to array
Object.entries(skillsMailchimpId)
  // Use `.forEach` to add properties to `outputSkills`
  .forEach(keyValuePair => {
    const [key, val] = keyValuePair;
    outputSkills[val] = skillsUser1.includes(key);
  });

console.log(outputSkills);

基本的想法是循环skillsMailchimpId而不是skillsUser。

但这不是很有活力。对于您的生产代码，您可能希望重构它以使其更灵活。

// Array of skills for one user    
const skillsUser1 = ["SKILL1", "SKILL3"]

// List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
  'SKILL1': 'list_id_1',
  'SKILL2': 'list_id_2',
  'SKILL3': 'list_id_3',
}

// Use `Object.entries` to transform `skillsMailchimpId` to array
const skillsMailchimpIdEntries = Object.entries(skillsMailchimpId);

const parseUserSkills = userSkills => {
  // Create an output object
  const outputSkills = {};
  
  // Use `.forEach` to add properties to `outputSkills`
  skillsMailchimpIdEntries.forEach(([key, val]) => {
    outputSkills[val] = userSkills.includes(key);
  });
  
  return outputSkills;
}

// Now you can use the function with any user
console.log(parseUserSkills(skillsUser1));