我有一个组件,我想在我的泽西休息api中使用而不使用request.resolve。我的web.xml看起来像这样
<!-- Jersey servlet configuration -->
<servlet>
<servlet-name>JerseyRESTServlet</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>com.cellularsouth.rest.SetApplication</param-value>
</init-param>
<!-- Params for JerseyServletWrapper servlet -->
<init-param>
<param-name>atg.service.jaxrs.JAXRSApplication.resourceRegistryPath</param-name>
<param-value>/atg/service/jaxrs/RestResourceRegistry</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>JerseyRESTServlet</servlet-name>
<url-pattern>/rest-api/*</url-pattern>
</servlet-mapping>
我创建了RestResouceRegistry.properties
并给了我这样的组件文件位置 -
nucleusRestResources+=\
/rest/api/account/Billing
但我没有在我的dyn / admin中看到RestResouceRegistry.properties。有人可以帮我弄清楚我错过了什么吗?
将服务的路径更改为默认的JAX-RS路径或将JerseyClassLoaderService.properties
更改为:
childFirstPrefixes=+\
/my/custom/service/path