在Spring Boot 2.0.4.RELEASE中的Rest Controller中捕获ArithmeticException

Question

我有一个基本的SpringBoot 2.0.4.RELEASE应用程序。使用Spring Initializer，JPA，嵌入式Tomcat，Thymeleaf模板引擎和包作为可执行的JAR文件。

我创建了这个类来管理异常：

@ControllerAdvice
@RestControllerAdvice
public class RestResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {

    public RestResponseEntityExceptionHandler() {
        super();
    }


    // 500

    @ExceptionHandler({ NullPointerException.class, IllegalArgumentException.class, IllegalStateException.class, RuntimeException.class })
    /*500*/
    @ResponseStatus(HttpStatus.INTERNAL_SERVER_ERROR)
    public BodyBuilder handleInternal(final RuntimeException ex, final WebRequest request) {
        logger.error("500 Status Code", ex);

        return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR);
    }
}

该方法处理RuntimeException，ArithmeticException扩展RuntimeException。

为了测试它，我创建了这个方法;

GetMapping(path = "/getUsers", consumes = "application/json", produces = "application/json")
public ResponseEntity<List<User>> testErrors(HttpServletRequest request) {

    double ss = 3 /0;

    return ResponseEntity.ok(userService.findAll());

}

期待这只会返回一个HttpStatus.INTERNAL_SERVER_ERROR，但它返回“

{"timestamp":"2018-08-31T09:21:21.717+0000","status":500,"error":"Internal Server Error","message":"/ by zero","trace":"java.lang.ArithmeticException: / by zero\n\tat ...

用这种方法

 @ExceptionHandler({ NullPointerException.class, IllegalArgumentException.class, IllegalStateException.class, RuntimeException.class })
    /*500*/
    public BodyBuilder handleInternal(final RuntimeException ex, final WebRequest request) {
        logger.error("500 Status Code", ex);
        return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR);
    }

我有完整的痕迹：{"timestamp":"2018-09-03T07:04:58.803+0000","status":500,"error":"Internal Server Error","message":"/ by zero","trace":"java.lang.ArithmeticException: / by zero\n\tat

有了这个，我在控制台中看不到有任何卷曲：

 @ExceptionHandler({ NullPointerException.class, IllegalArgumentException.class, IllegalStateException.class, RuntimeException.class })
    /*500*/
    @ResponseStatus(HttpStatus.INTERNAL_SERVER_ERROR)
    public void handleInternal(final RuntimeException ex, final WebRequest request) {
        logger.error("500 Status Code", ex);

    }

而另一个，在控制台中也没有任何东西：

@ExceptionHandler({ NullPointerException.class, IllegalArgumentException.class, IllegalStateException.class, RuntimeException.class })
    /*500*/
    public ResponseEntity<Object> handleInternal(final RuntimeException ex, final WebRequest request) {
        logger.error("500 Status Code", ex);


        return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR).build();

    }

Answer 1

也许piradian没有具体指出它，但问题似乎是你的handleInternal方法的返回类型。在您提供的代码中，返回类型为BodyBuilder，并返回ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR)返回的值。实际上，正如BodyBuilder的名字所暗示的那样，它代表了Builder pattern的实现。在这种情况下你应该做的是：

return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR).build();

并将方法的返回类型更改为ResponseEntity或ResponseEntity<Object>（在您的情况下，正文是空的，因此确实没有太大区别）。

但是，考虑到你的例子中没有返回任何体，你已经用@ResponseStatus(HttpStatus.INTERNAL_SERVER_ERROR)注释了你的方法，你所能做的就是将返回类型改为void而不返回任何东西 - 这正是piradian建议的。这也应该有用。

Answer 2

试试这个：

@ExceptionHandler({NullPointerException.class, IllegalArgumentException.class, IllegalStateException.class, RuntimeException.class})
/* 500 */
@ResponseStatus(HttpStatus.INTERNAL_SERVER_ERROR)
public void handleInternal(final RuntimeException ex, final WebRequest request) {
    logger.error("500 Status Code", ex);

}

Answer 3

用这个

@RestControllerAdvice//insted of @ControllerAdvice
public class RestResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {    
   @ExceptionHandler(value = { Exception.class, RuntimeException.class })
    @ResponseStatus(HttpStatus.INTERNAL_SERVER_ERROR)
    public BodyBuilder handleInternal(final RuntimeException ex, final WebRequest request) {
        logger.error("500 Status Code", ex);

        return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR);
    }
}