Android:可以将参数从CursorAdapter传递到Service

问题描述 投票:2回答:1

我只想传递一个从游标到Service的变量。但总是得到一个NullPointerException

这是我的适配器,我用它来向listView显示数据。

public class DetailCategoryCursorAdapter extends CursorAdapter{

private Services services;

public DetailCategoryCursorAdapter(Context context, Cursor c) {
    super(context, c);
}

@Override
public View newView(Context context, Cursor cursor, ViewGroup parent) {
    return LayoutInflater.from(context).inflate(R.layout.list_item_detail, parent, false);
}

@Override
public void bindView(View view, final Context context, Cursor cursor) {

TextView titleTextView = (TextView) view.findViewById(R.id.title);
        ImageView imageView = (ImageView) view.findViewById(R.id.dplay);

int titleColumnIndex = cursor.getColumnIndex(Contract.Entry.COLUMN_TITLE);

int urlColumnIndex = cursor.getColumnIndex(Contract.Entry.COLUMN_URL);

    String title = cursor.getString(titleColumnIndex);
    String url = cursor.getString(urlColumnIndex);

    nameTextView.setText(title);

    imageView.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            try {
                Intent sIntent = new Intent(context, Services.class);
                sIntent.putExtra("url", url);
                services.startService(sIntent); // in this part always show NullPointerEception
                Log.v("url", url);
            }catch (Exception e){
                e.printStackTrace();
            }
        }
    });
}
}

或者有更好的方法吗?需要建议。谢谢

android android-service android-cursoradapter
1个回答
1
投票

在你的onBind中使用它不会抛出异常。 (因为你的services为null)

Intent sIntent = new Intent(context, Services.class);
            sIntent.putExtra("url", url);
            context.startService(sIntent);
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