如果存在,如何从BackStack恢复Fragment

问题描述 投票:131回答:6

我正在学习如何使用片段。我有三个Fragment实例,它们在课程顶部初始化。我将片段添加到这样的活动:

声明和初始化:

Fragment A = new AFragment();
Fragment B = new BFragment();
Fragment C = new CFragment();

更换/添加:

FragmentTransaction ft = getSupportFragmentManager().beginTransaction();
ft.replace(R.id.content_frame, A);
ft.addToBackStack(null);
ft.commit();

这些片段工作正常。每个片段都附加到活动,并保存到后台堆栈没有任何问题。

因此,当我启动AC,然后B时,堆栈看起来像这样:

| |
|B|
|C|
|A|
___

当我按下“后退”按钮时,B被摧毁,C被恢复。

但是,当我第二次启动片段A时,它不会从后端堆栈恢复,而是添加到后端堆栈的顶部

| |
|A|
|C|
|A|
___

但我想恢复A并摧毁它上面的所有碎片(如果有的话)。实际上,我只是喜欢默认的后台堆栈行为。

我该如何做到这一点?

预期:(应恢复A并销毁顶部碎片)

| |
| |
| |
|A|
___

编辑:(由A - C建议)

这是我尝试的代码:

private void selectItem(int position) {
        Fragment problemSearch = null, problemStatistics = null;
        FragmentManager manager = getSupportFragmentManager();
        FragmentTransaction ft = manager.beginTransaction();
        String backStateName = null;
        Fragment fragmentName = null;
        boolean fragmentPopped = false;
        switch (position) {
        case 0:
            fragmentName = profile;
            break;
        case 1:
            fragmentName = submissionStatistics;
            break;
        case 2:
            fragmentName = solvedProblemLevel;
            break;
        case 3:
            fragmentName = latestSubmissions;
            break;
        case 4:
            fragmentName = CPExercise;
            break;
        case 5:
            Bundle bundle = new Bundle();
            bundle.putInt("problem_no", problemNo);
            problemSearch = new ProblemWebView();
            problemSearch.setArguments(bundle);
            fragmentName = problemSearch;
            break;
        case 6:
            fragmentName = rankList;
            break;
        case 7:
            fragmentName = liveSubmissions;
            break;
        case 8:
            Bundle bundles = new Bundle();
            bundles.putInt("problem_no", problemNo);
            problemStatistics = new ProblemStatistics();
            problemStatistics.setArguments(bundles);
            fragmentName = problemStatistics;
        default:
            break;
        }
        backStateName = fragmentName.getClass().getName();
        fragmentPopped = manager.popBackStackImmediate(backStateName, 0);
        if (!fragmentPopped) {
            ft.replace(R.id.content_frame, fragmentName);
        }
        ft.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_FADE);
        ft.addToBackStack(backStateName);
        ft.commit();

        // I am using drawer layout
        mDrawerList.setItemChecked(position, true);
        setTitle(title[position]);
        mDrawerLayout.closeDrawer(mDrawerList);
    }

问题是,当我启动A然后B,然后按'后退',B被删除,A恢复。然后第二次按'后退'应退出应用程序。但是它显示一个空白窗口,我必须再次按回来关闭它。

此外,当我发射A,然后B,然后C,然后B再次...

预期:

| |
| |
|B|
|A|
___

实际:

| |
|B|
|B|
|A|
___

我应该用任何自定义覆盖onBackPressed()还是我错过了什么?

android android-fragments back-stack
6个回答
262
投票

读取documentation,有一种方法可以根据事务名称或commit提供的id弹出后台堆栈。使用该名称可能更容易,因为它不需要跟踪可能改变的数字并加强“唯一的后栈条目”逻辑。

由于每个Fragment只需要一个后向堆栈条目,因此将后面的状态名称设为Fragment的类名(通过getClass().getName())。然后当替换Fragment时,使用popBackStackImmediate()方法。如果返回true,则表示后端堆栈中存在Fragment的实例。如果没有,实际执行Fragment替换逻辑。

private void replaceFragment (Fragment fragment){
  String backStateName = fragment.getClass().getName();

  FragmentManager manager = getSupportFragmentManager();
  boolean fragmentPopped = manager.popBackStackImmediate (backStateName, 0);

  if (!fragmentPopped){ //fragment not in back stack, create it.
    FragmentTransaction ft = manager.beginTransaction();
    ft.replace(R.id.content_frame, fragment);
    ft.addToBackStack(backStateName);
    ft.commit();
  }
}

编辑

问题是 - 当我启动A然后启动B,然后按回按钮,B被移除并且A被恢复。并再次按下后退按钮应该退出应用程序。但它显示一个空白窗口,需要另一个按下来关闭它。

这是因为FragmentTransaction被添加到后栈以确保我们可以稍后将片段弹出。一个快速解决方法是覆盖onBackPressed()并完成活动,如果后面的堆栈只包含1个Fragment

@Override
public void onBackPressed(){
  if (getSupportFragmentManager().getBackStackEntryCount() == 1){
    finish();
  }
  else {
    super.onBackPressed();
  }
}

关于重复的后备栈条目,如果片段尚未弹出,则替换片段的条件语句明显不同于我的原始代码片段。无论后备堆栈是否弹出,您正在做的是添加到后台堆栈。

这样的东西应该更接近你想要的东西:

private void replaceFragment (Fragment fragment){
  String backStateName =  fragment.getClass().getName();
  String fragmentTag = backStateName;

  FragmentManager manager = getSupportFragmentManager();
  boolean fragmentPopped = manager.popBackStackImmediate (backStateName, 0);

  if (!fragmentPopped && manager.findFragmentByTag(fragmentTag) == null){ //fragment not in back stack, create it.
    FragmentTransaction ft = manager.beginTransaction();
    ft.replace(R.id.content_frame, fragment, fragmentTag);
    ft.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_FADE);
    ft.addToBackStack(backStateName);
    ft.commit();
  } 
}

条件有点改变,因为选择相同的片段,而它可见也导致重复条目。

执行:

我强烈建议不要像你在代码中那样分开更新的replaceFragment()方法。所有逻辑都包含在此方法中,并且移动部件可能会导致问题。

这意味着您应该将更新的replaceFragment()方法复制到您的班级然后更改

backStateName = fragmentName.getClass().getName();
fragmentPopped = manager.popBackStackImmediate(backStateName, 0);
if (!fragmentPopped) {
            ft.replace(R.id.content_frame, fragmentName);
}
ft.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_FADE);
ft.addToBackStack(backStateName);
ft.commit();

所以很简单

replaceFragment (fragmentName);

编辑#2

要在后台堆栈更改时更新抽屉,请创建一个在片段中接受的方法并比较类名称。如果匹配,请更改标题和选择。如果有一个有效的片段,还要添加一个OnBackStackChangedListener并让它调用你的更新方法。

例如,在Activity的onCreate()中,添加

getSupportFragmentManager().addOnBackStackChangedListener(new OnBackStackChangedListener() {

  @Override
  public void onBackStackChanged() {
    Fragment f = getSupportFragmentManager().findFragmentById(R.id.content_frame);
    if (f != null){
      updateTitleAndDrawer (f);
    }

  }
});

另一种方法:

private void updateTitleAndDrawer (Fragment fragment){
  String fragClassName = fragment.getClass().getName();

  if (fragClassName.equals(A.class.getName())){
    setTitle ("A");
    //set selected item position, etc
  }
  else if (fragClassName.equals(B.class.getName())){
    setTitle ("B");
    //set selected item position, etc
  }
  else if (fragClassName.equals(C.class.getName())){
    setTitle ("C");
    //set selected item position, etc
  }
}

现在,每当后台堆栈发生变化时,标题和检查位置将反映可见的Fragment


8
投票

我认为这种方法可以解决你的问题:

public static void attachFragment ( int fragmentHolderLayoutId, Fragment fragment, Context context, String tag ) {


    FragmentManager manager = ( (AppCompatActivity) context ).getSupportFragmentManager ();
    FragmentTransaction ft = manager.beginTransaction ();

    if (manager.findFragmentByTag ( tag ) == null) { // No fragment in backStack with same tag..
        ft.add ( fragmentHolderLayoutId, fragment, tag );
        ft.addToBackStack ( tag );
        ft.commit ();
    }
    else {
        ft.show ( manager.findFragmentByTag ( tag ) ).commit ();
    }
}

最初发布在This Question


3
投票

第1步:使用您的活动类实现接口

public class AuthenticatedMainActivity extends Activity implements FragmentManager.OnBackStackChangedListener{

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        .............
        FragmentManager fragmentManager = getFragmentManager();           
        fragmentManager.beginTransaction().add(R.id.frame_container,fragment, "First").addToBackStack(null).commit();
    }

    private void switchFragment(Fragment fragment){            
      FragmentManager fragmentManager = getFragmentManager();
      fragmentManager.beginTransaction()
        .replace(R.id.frame_container, fragment).addToBackStack("Tag").commit();
    }

    @Override
    public void onBackStackChanged() {
    FragmentManager fragmentManager = getFragmentManager();

    System.out.println("@Class: SummaryUser : onBackStackChanged " 
            + fragmentManager.getBackStackEntryCount());

    int count = fragmentManager.getBackStackEntryCount();

    // when a fragment come from another the status will be zero
    if(count == 0){

        System.out.println("again loading user data");

        // reload the page if user saved the profile data

        if(!objPublicDelegate.checkNetworkStatus()){

            objPublicDelegate.showAlertDialog("Warning"
                    , "Please check your internet connection");

        }else {

            objLoadingDialog.show("Refreshing data..."); 

            mNetworkMaster.runUserSummaryAsync();
        }

        // IMPORTANT: remove the current fragment from stack to avoid new instance
        fragmentManager.removeOnBackStackChangedListener(this);

    }// end if
   }       
}

第2步:当您调用另一个片段时,添加以下方法:

String backStateName = this.getClass().getName();

FragmentManager fragmentManager = getFragmentManager();
fragmentManager.addOnBackStackChangedListener(this); 

Fragment fragmentGraph = new GraphFragment();
Bundle bundle = new Bundle();
bundle.putString("graphTag",  view.getTag().toString());
fragmentGraph.setArguments(bundle);

fragmentManager.beginTransaction()
.replace(R.id.content_frame, fragmentGraph)
.addToBackStack(backStateName)
.commit();

0
投票
getFragmentManager().addOnBackStackChangedListener(new FragmentManager.OnBackStackChangedListener() {

    @Override
    public void onBackStackChanged() {

        if(getFragmentManager().getBackStackEntryCount()==0) {
            onResume();
        }    
    }
});

0
投票

更容易的解决方案将改变这条线

ft.replace(R.id.content_frame, A);ft.add(R.id.content_frame, A);

在你的XML布局中,请使用

  android:background="@color/white"
  android:clickable="true"
  android:focusable="true"

Clickable表示它可以被指针设备点击或被触摸设备点击。

Focusable意味着它可以从键盘等输入设备获得焦点。键盘等输入设备无法根据输入本身决定将输入事件发送到哪个视图,因此将它们发送到具有焦点的视图。


0
投票

我知道回答这个问题已经很晚了,但我自己解决了这个问题,并且认为值得与大家分享

public void replaceFragment(BaseFragment fragment) {
    FragmentTransaction transaction = getSupportFragmentManager().beginTransaction();
    final FragmentManager fManager = getSupportFragmentManager();
    BaseFragment fragm = (BaseFragment) fManager.findFragmentByTag(fragment.getFragmentTag());
    transaction.setCustomAnimations(R.anim.enter_from_right, R.anim.exit_to_left, R.anim.enter_from_left, R.anim.exit_to_right);

    if (fragm == null) {  //here fragment is not available in the stack
        transaction.replace(R.id.container, fragment, fragment.getFragmentTag());
        transaction.addToBackStack(fragment.getFragmentTag());
    } else { 
        //fragment was found in the stack , now we can reuse the fragment
        // please do not add in back stack else it will add transaction in back stack
        transaction.replace(R.id.container, fragm, fragm.getFragmentTag()); 
    }
    transaction.commit();
}

并在onBackPressed()

 @Override
public void onBackPressed() {
    if(getSupportFragmentManager().getBackStackEntryCount()>1){
        super.onBackPressed();
    }else{
        finish();
    }
}
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