poloniex 403禁止使用python3.5

Question

我正在尝试创建与poloniex的基本身份验证连接，并且我不断从其API返回403 forbidden错误。

time import time
import urllib.request
import urllib.parse
import hashlib
import hmac

APIkey = b'provert-kee'
secret = b'ceecret'
url = 'https://poloniex.com/tradingApi'

payload = {
    'command': 'returnBalances',
    'nonce': int(time() * 1000),
}

paybytes = urllib.parse.urlencode(payload).encode('utf8')
print(paybytes)

sign = hmac.new(secret, paybytes, hashlib.sha512).hexdigest()
print(sign)

headers = {
    'Key': APIkey,
    'Sign': sign,
}

req = urllib.request.Request(url, headers=headers, data=paybytes)
with urllib.request.urlopen(req) as response:
    the_page = response.read()
    print(the_page)

输出：

#python3 apicalltest3.py 
b'command=returnBalances&nonce=1498380606389'
5555555
Traceback (most recent call last):
  File "apicalltest3.py", line 29, in <module>
    with urllib.request.urlopen(req) as response:
  File "/usr/lib/python3.5/urllib/request.py", line 163, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib/python3.5/urllib/request.py", line 472, in open
    response = meth(req, response)
  File "/usr/lib/python3.5/urllib/request.py", line 582, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib/python3.5/urllib/request.py", line 510, in error
    return self._call_chain(*args)
  File "/usr/lib/python3.5/urllib/request.py", line 444, in _call_chain
    result = func(*args)
  File "/usr/lib/python3.5/urllib/request.py", line 590, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden

在他们的支持页面上，他们使用hmac 512在python2.7中有一个样本包装器

API doc

如何获得与poloniex的基本身份验证连接？

Answer 1

据the Official Documentation说：

'b'：二进制格式。输出基数2中的数字。

在你的代码中，你提供密钥和秘密作为binary，但它必须是一个string

所以请更换：

APIkey = b'provert-kee'
secret = b'ceecret'

通过

APIkey = 'provert-kee' # or s'provert-kee'
secret = 'ceecret' # or s'ceecret'