无效的PathExpression必须是StateFieldPathExpression [重复]

Question

这个问题与以下内容完全相同：

• Invalid PathExpression. Must be a StateFieldPathExpression 1回答

我目前正在使用Symfony3.4进行一个项目，一个项目是关于预订酒店的房间。 我有两个实体room(id,...)和bookings(room,check_in,check_out,...)，它们之间的关系是OneToMany。 我正在尝试检索未被check_in和check_out字段预订的房间。 我在RoomRepository做了一个名为findRoomsNotBookedByCheckInCheckOut的函数

public function findRoomsNotBookedByCheckInCheckOut(Request $request) {
        $em = $this->getEntityManager();

        $q = $em->createQuery("SELECT r FROM AppBundle:Room r "
        . "WHERE r NOT IN ( "
        . "SELECT b.room FROM AppBundle:Bookings b "
        . "WHERE NOT ( "
        . "b.checkOut <= :checkIn "
        . "OR b.checkIn >= :checkOut "
        . ") "
        . ") ORDER BY r.id")
        ->setParameter('checkIn', "'".$request->query->get('check-out')."'")
        ->setParameter('checkOut', "'".$request->query->get('check-in')."'");

        die($q->getSQL());
        return $q->getResult();
    }  

当我从控制器调用此功能时

private function roomsByCheckInCheckOut(Request $request, $em) {
        if ($request->query->get('check-in') != null && $request->query->get('check-out') != null) {

           $rooms = $em->getRepository('AppBundle:Room')->findRoomsNotBookedByCheckInCheckOut($request);

        }
        return null;
    }  

我收到的错误是：

[Semantical Error] line 0, col 57 near 'room FROM AppBundle:Bookings': Error: Invalid PathExpression. Must be a StateFieldPathExpression.  

我试图通过将b.room更改为b.room.id来修复：

public function findRoomsNotBookedByCheckInCheckOut(Request $request) {
        $em = $this->getEntityManager();

        $q = $em->createQuery("SELECT r FROM AppBundle:Room r "
        . "WHERE r NOT IN ( "
        . "SELECT b.room.id FROM AppBundle:Bookings b "
        . "WHERE NOT ( "
        . "b.checkOut <= :checkIn "
        . "OR b.checkIn >= :checkOut "
        . ") "
        . ") ORDER BY r.id")
        ->setParameter('checkIn', "'".$request->query->get('check-out')."'")
        ->setParameter('checkOut', "'".$request->query->get('check-in')."'");

        die($q->getSQL());
        return $q->getResult();
    }

我得到另一个错误：

[Semantical Error] line 0, col 62 near 'id FROM AppBundle:Bookings': Error: Class AppBundle\Entity\Bookings has no field or association named room.id

这是逻辑，因为实体bookings没有room.id但它有room。 我再次尝试通过将b.room更改为b来解决，函数变为：

public function findRoomsNotBookedByCheckInCheckOut(Request $request) {
        $em = $this->getEntityManager();

        $q = $em->createQuery("SELECT r FROM AppBundle:Room r "
        . "WHERE r NOT IN ( "
        . "SELECT b FROM AppBundle:Bookings b "
        . "WHERE NOT ( "
        . "b.checkOut <= :checkIn "
        . "OR b.checkIn >= :checkOut "
        . ") "
        . ") ORDER BY r.id")
        ->setParameter('checkIn', "'".$request->query->get('check-out')."'")
        ->setParameter('checkOut', "'".$request->query->get('check-in')."'");

        die($q->getSQL());
        return $q->getResult();
    }

它工作正常，没有任何错误，但它没有找到正确的结果。 注意：我在MySQL数据库中测试了sql查询，得到了正确的结果

Answer 1

我刚刚通过添加IDENTITY(b.room)解决了我的问题。

$q = $em->createQuery("SELECT r.id FROM AppBundle:Room r "
        . "WHERE r.id NOT IN ( "
        . "SELECT IDENTITY(b.room) FROM AppBundle:Bookings b "
        . "WHERE NOT ( "
        . "b.checkOut < :checkIn "
        . "OR b.checkIn > :checkOut "
        . ") "
        . ") ORDER BY r.id")
        ->setParameter('checkIn', $chIn)
        ->setParameter('checkOut', $chOut);