违反常态:元素类型无效:预期为字符串(用于内置组件)

问题描述 投票:0回答:1

反应本机模拟器给出错误“不变违反:元素类型无效:预期为字符串(对于内置组件)或类/函数(对于复合组件),但得到了:对象。您可能忘记了从其定义的文件中导出组件,或者可能混淆了默认名称和命名导入。

App.js

import React, { Component } from 'react';
import {
  SafeAreaView,
  StyleSheet,
  ScrollView,
  View,
  NavigatorIOS,
  Text,
  StatusBar,
} from 'react-native';
import {
  Header,
  LearnMoreLinks,
  Colors,
  DebugInstructions,
  ReloadInstructions,
} from 'react-native/Libraries/NewAppScreen';

import SearchPage from './SearchPage';

export default class App extends Component<{}> {
  render() {
    return (
      <NavigatorIOS
        style={styles.container}
        initialRoute={{
          title: 'Property Finder',
          component: SearchPage,
        }}/>
    );
}
}


const styles = StyleSheet.create({
    container: {
  flex: 1,
},
});

SearchPage.js

import React, { Component } from 'react';
import {
  StyleSheet,
  Text,
  TextInput,
  View,
  Button,
  ActivityIndicator,
  Image,
} from 'react-native';;

export default class SearchPage extends Component<{}> {
  render() {
    return (
      <View style={styles.container}>
        <Text style={styles.description}>
          Search for houses to buy!
        </Text>
        <Text style={styles.description}>
          Search by place-name or postcode.
        </Text>
      </View>
    );
  }
}

const styles = StyleSheet.create({
  description: {
    marginBottom: 20,
    fontSize: 18,
    textAlign: 'center',
    color: '#656565'
  },
  container: {
    padding: 30,
    marginTop: 65,
    alignItems: 'center'
  },
});

Simulator showing this when I'm running the code.

有人可以告诉其中的问题。使用本机版本:0.61

react-native
1个回答
0
投票

您遇到的错误通常发生在您可能忘记了从定义文件中导出组件时。我看到您的代码已完成。我运行您的代码。它显示NavigatorIOS已从库中删除。而且我认为它是由NavigatorIOS引起的,仅在ios上有效且已弃用。您应该使用“ react-native-navigationorreact-native-router-flux”,建议您使用react-native-router-flux。如果使用react-native-router-flux,则可以查看以下代码:

const App = () => (
  <Router>
    <Stack key="root">
      <Scene key="search" component={SearchParge} title="search" />
    </Stack>
  </Router>

// then, if you want to go to it
Actions.search()
);



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