我正在使用cx_Freeze版本5.1.1,我有一个python 2.7.9应用程序来使用cx_Freeze进行打包。应用程序使用python'requests'模块(请求的版本是2.18.4)
这是我的cx_Freeze setup.py文件(注意我特意在包中包含'requests'):
from cx_Freeze import setup, Executable
import sys
from cx_Freeze import setup, Executable
packages_to_include =['lib','lib/DB','encodings.ascii','requests']
buildOptions = dict(
optimize=1,
excludes = ['tkinter'],
bin_includes = [
'libcrypto.so.1.0.0',
'libcrypto.so.10',
'libgssapi_krb5.so.2',
'libk5crypto.so.3',
'libkeyutils.so.1',
'libssl.so.1.0.1e',
'libssl.so.10'
],
includes = packages_to_include,
packages= ['urllib3','idna']
)
executables = [
Executable(
'workapp.py',
targetName = 'workapp'
)
]
setup(
name='Sample Flask App',
version = '0.1',
description = 'Sample Flask App',
#requires = ["requests"],
options = dict(build_exe = buildOptions),
executables = executables
)
构建完成成功创建可执行文件,但在运行我的应用程序时,我收到以下错误:
Traceback (most recent call last):
File "/usr/local/lib/python2.7/site-packages/cx_Freeze/initscripts/__startup__.py", line 14, in run
module.run()
File "/usr/local/lib/python2.7/site-packages/cx_Freeze/initscripts/Console.py", line 26, in run
exec(code, m.__dict__)
File "vaas.py", line 2, in <module>
import requests
File "/usr/local/lib/python2.7/site-packages/requests/__init__.py", line 113, in <module>
from . import packages
ImportError: cannot import name packages
我认为这是我的cx_Freeze设置或请求的问题,但由于我告诉cx_Freeze包含'requests',这应该有效。我检查了构建目录(cx_Freeze构建了请求模块定义了'packages',我可以找到它:
[user@centos-vm]$ ls build/exe.linux-x86_64-2.7/lib/requests/packages/
chardet idna urllib3
任何帮助深表感谢!
找到了解决此问题的方法:
编辑:
/usr/local/lib/python2.7/site-packages/requests/__init__.py
并注释掉:
from . import packages
确实很奇怪的问题。我的未冻结的应用程序工作正常,但使用cx_freeze时需要上面的解决方法。
尝试将'request'
添加到packages
列表选项,而不是将其添加到includes
列表选项:
packages= ['urllib3', 'idna', 'requests']
根据cx_Freeze
documentation,build_exe
选项includes
是一个
逗号分隔的要包含的模块名称列表
而build_exe
选项packages
是一个
逗号分隔要包括的包列表,其中包括包中的所有子模块