我有一列百分比,其中包含像0.4567 , 0.1564 , 19 , 23, 0 , 0.1234
这样的数字,需要对整数进行标准化,即45 , 15, 19 ,23 , 0 , 12
这样。我转载了如下示例。
import pandas as pd
import numpy as np
n_row = 10
dicti = {'id':[coli for coli in range(1,(n_row+1))],
'perc_col':[30,0.4546,0.76543223190,10,0,0.29567,93,15,0.31,0.456]}
df = pd.DataFrame(dicti)
df
数据帧输出
您可以通过这样的列表理解来做到这一点:
import pandas as pd
import numpy as np
n_row = 10
dicti = {'id':[coli for coli in range(1,(n_row+1))],
'perc_col':[int(x) if x > 1 else int(x*100) for x in [30,0.4546,0.76543223190,10,0,0.29567,93,15,0.31,0.456] ]}
df = pd.DataFrame(dicti)
df
输出
id perc_col
0 1 30
1 2 45
2 3 76
3 4 10
4 5 0
5 6 29
6 7 93
7 8 15
8 9 31
9 10 45