从JavaScript工作日获取下一个日期

Question

如何返回给定工作日的下一个日期（可以是0-6号或者周日至周六的名字）。

例如今天，在2009年10月16日星期五，我通过了：

• 星期五，它将于2009年10月16日至今日返回
• 星期六返回2009年10月17日
• 周四将于2009年10月22日返回

Answer 1

只添加7并不能解决问题。

以下功能将为您提供一周的第二天。

function nextDay(x){
    var now = new Date();    
    now.setDate(now.getDate() + (x+(7-now.getDay())) % 7);
    return now;
}

Answer 2

以下是蒂姆回答解决具体问题的一个略微修改的版本 - 传递日期d，以及所需的星期几（道具0-6），返回日期

function nextDay(d, dow){
    d.setDate(d.getDate() + (dow+(7-d.getDay())) % 7);
    return d;
}

Answer 3

这是另一个简单的解决方案

//takes dayIndex from sunday(0) to saturday(6)
function nextDate(dayIndex) {
    var today = new Date();
    today.setDate(today.getDate() + (dayIndex - 1 - today.getDay() + 7) % 7 + 1);
    return today;
}
document.write("Next Sunday is: "+nextDate(0).toLocaleString()+"<br/>");
document.write("Next Thursday is: "+nextDate(4).toLocaleString()+"<br/>");
document.write("Next Saturday is: "+nextDate(6).toLocaleString());

Answer 4

要扩展user 190106的answer，此代码应该为您提供所需的内容：

function getNextDay(day, resetTime){
  var days = {
    sunday: 0, monday: 1, tuesday: 2,
    wednesday: 3, thursday: 4, friday: 5, saturday: 6
  };

  var dayIndex = days[day.toLowerCase()];
  if (dayIndex !== undefined) {
    throw new Error('"' + day + '" is not a valid input.');
  }

  var returnDate = new Date();
  var returnDay = returnDate.getDay();
  if (dayIndex !== returnDay) {
    returnDate.setDate(returnDate.getDate() + (dayIndex + (7 - returnDay)) % 7);
  }

  if (resetTime) {
    returnDate.setHours(0);
    returnDate.setMinutes(0);
    returnDate.setSeconds(0);
    returnDate.setMilliseconds(0);
  }
  return returnDate;
}

alert(getNextDay('thursday', true));

Answer 5

如果你不想传递数字而是工作日名称（星期日 - 星期六）来查找某个工作日的未来日期，那么这也有助于你：

function getDateOfWeekday(refday){
    var days = {
        monday: 1,
        tuesday: 2,
        wednesday: 3,
        thursday: 4,
        friday: 5,
        saturday: 6,
        sunday: 0
    };
    if(!days.hasOwnProperty(refday))throw new Error(refday+" is not listed in "+JSON.stringify(days));
    var currDate = new Date();
    var currTimestamp = currDate.getTime();
    var triggerDay = days[refday];
    var dayMillDiff=0;
    var dayInMill = 1000*60*60*24;
    // add a day to dayMillDiff as long as the desired refday (sunday for instance) is not reached
    while(currDate.getDay()!=triggerDay){
        dayMillDiff += dayInMill;
        currDate = new Date(currDate.getTime()+dayInMill);
    }
    return new Date(currTimestamp + dayMillDiff);
}

var sunday = getDateOfWeekday("sunday");
document.write("Next Sunday is at: <strong>"+sunday.toLocaleString()+"</strong><br/>");

var thursday = getDateOfWeekday("thursday");
thursday.setHours(0,0,0,0); // set hours/minutes/seconds and millseconds to zero
document.write("Next Thursday is at: <strong>"+thursday.toLocaleString()+"</strong> on midnight<br/>");

var tuesday = getDateOfWeekday("tuesday");
document.write("Next Tuesday is at: <strong>"+tuesday.toLocaleString()+"</strong><br/>");

Answer 6

用于javascript DateTime programming的瑞士刀具。

http://www.datejs.com/