如何访问Python中函数调用的上游函数

Question

为了调试在我的代码中观察到的警告，我试图找到一种方法来以编程方式识别我的代码调用的函数堆栈。

举个例子

def func(x):
    return func2(x+4)

def func2(x):
    return x*3

func(5)

对于上面的代码我想看到类似的东西

func(5)
- func2(9)

Answer 1

pdb

（和其他调试器）可以做到这一点（已添加评论）：

C:\>py -m pdb test.py              # debug your script
> c:\test.py(1)<module>()
-> def func(x):
(Pdb) l                            # list lines around current instruction
  1  -> def func(x):
  2         return func2(x+4)
  3
  4     def func2(x):
  5         return x*3
  6
  7     func(5)
[EOF]
(Pdb) b 5                                     # breakpoint in func2 (line 5)
Breakpoint 1 at c:\users\metolone\test.py:5
(Pdb) r                                       # run to breakpoint
> c:\users\metolone\test.py(5)func2()         # in func2()
-> return x*3
(Pdb) x                                       # x (the parameter) was 9
9
(Pdb) where                                   # display call stack
  c:\dev\python312\lib\bdb.py(600)run()
-> exec(cmd, globals, locals)
  <string>(1)<module>()
  c:\users\metolone\test.py(7)<module>()
-> func(5)                                      # func(5) called
  c:\users\metolone\test.py(2)func()
-> return func2(x+4)                            # func2 called (what was x?)
> c:\users\metolone\test.py(5)func2()
-> return x*3                                   # in func2
(Pdb) x                                         # x == 9
9
(Pdb) up                                        # move up stack frame
> c:\users\metolone\test.py(2)func()
-> return func2(x+4)                            # now in func()
(Pdb) x                                         # x == 5 when about to call func2()
5